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How to make a Gtk+ widget overlap an osgGtk widget

Posted on 2010-11-18
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Last Modified: 2012-05-10
Hello Experts!

I have a Gtk+ application with a widget that displays an OSG view using the osgGtk project (see http://sourceforge.net/projects/osggtk/).

I am using a gtk_fixed widget so that I can place all of my widgets exactly where I want them, and I want to make the OSG widget the size of the entire screen and then place buttons, images, etc. on top of the OSG widget.

Normally I can use the gtk_fixed to make widgets overlap if I want to, but the osgGtk widget is always on top of everything else, despite my best efforts. Is there a way to tell Gtk+ that I always want a widget to appear in the foreground, on top of whatever is behind it? I'll post some skeleton code to show what I'm doing below.

Please let me know how I can help and thanks in advance for your help!

P.S. There's no Gtk+ or OSG zones in Experts Exchange, so if anyone can suggest a different zone than what I've listed, please let me know!
GtkWidget *pFixedContainer;

GtkWidget *pFrameImage;

GtkWidget *pOsgWidget;



...

// make the image widget and the osg widget

...



gtk_widget_set_size_request(pOsgWidget, SCREEN_WIDTH, SCREEN_HEIGHT);



gtk_widget_set_size_request(pFrameImage, 100, 50);



...



gtk_fixed_put(GTK_FIXED(pFixedContainer), pOsgWidget, 0, 0);

gtk_fixed_put(GTK_FIXED(pFixedContainer), pFrameImage, 100, 100);



// I want the pFrameImage to be on top of the pOsgWidget, but the pOsgWidget is always on top!

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Question by:ehensens
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Expert Comment

by:Duncan Roe
ID: 34177462
"Always on top" is is implemented by the Window Manager. I know you can talk to the WM in Tk (which is about the extent of my graphics experience) - can you do it with GTK?
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Accepted Solution

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ehensens earned 0 total points
ID: 34485733
I had forgotten about this question, I apologize for letting it go abandoned. The answer to this question is that the Gtk widget that you display from the osgGtk source is derived from a GtkDrawingArea widget, which does not have a transparent background.
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Author Closing Comment

by:ehensens
ID: 34514866
I am accepting my own solution because there was not much feedback, and I found out the answer on my own.
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