convert square matrix to 3-column list

Hi. I have a symmetric square matrix (see attached file as sample). I need to convert it to a three column list (I only need either the upper triangular part or the lower triangular part since it is symmetric).
Can anyone give me a perl script that will do it? The actual matrix will be a csv file called similarityM.csv and will only contain the matrix.
With the attached matrix I would want to arrive at something like the following (the '...' mean etc)

allwineclub      amazing      -0.007007171
allwineclub      awesome      -0.005773905
amazing      awesome      0.019403651
amazing      back      -0.001234014
awesome      back      -0.00770258

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ozoConnect With a Mentor Commented:
perl -F, -lane 'print "$F[0]\t$h[$_]\t$F[$_]" for $...$#h;@h=@F if !@h' similarityM.csv
onyourmarkAuthor Commented:
Thanks I tried it but I got this:

C:\Users\Bill\Desktop\similarity>C:\Perl\bin/perl -F, -lane 'print "$F[0]\t$h[$_
]\t$F[$_]" for $...$#h;@h=@F if !@h' similarityM.csv
Can't find string terminator "'" anywhere before EOF at -e line 1.
Justin MathewsCommented:
@ozo's solution above works fine. I gather you are running it on Windows. So just enclose the script in double quotes and escape the double quotes inside the script as:

perl -F, -lane "print \"$F[0]\t$h[$_]\t$F[$_]\" for $...$#h;@h=@F if !@h" similarityM.csv

BTW: This is not for points.
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onyourmarkAuthor Commented:
onyourmarkAuthor Commented:
Hi. Thanks very much. Could you explain a little of how this code works?
-n  loops over input lines
-a  splits into @F
-F,  uses /,/ to split on
-l  removes line terminators from input and adds line terminators to the output
 for $. .. $#h  loops from the current line number to the index of the last entry in @h
@h=@F if !@h  gets the header names
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