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Remove duplicates in random number generator

Posted on 2010-11-23
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1,346 Views
Last Modified: 2012-05-10
I am confused on how to use LINQ and remove duplicate numbers from  my random number generator below is the code that I have written
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Cunningham_CSC153_A13_P2
{
    class Program
    {
        static void Main(string[] args)
        {
            Random randomNumber = new Random();

            int[] num;
            num = new int[20];

            List<int> ranNum = new List<int>();

            for(int count = 0; count <= 29; count++)
            {
                //List<int> ranNum = new List<int>();
                ranNum.Add(randomNumber.Next(1,20));
                

               
               
            }
            var sortRanNum =
                 from value in ranNum
                 orderby value
                 select value;

            Display(sortRanNum, "Random Numbers sorted in ascending order");

            Console.WriteLine();

            var sortDecRanNum =
                 from value in ranNum
                 orderby value descending
                 select value;

            Display(sortDecRanNum, "Random Numbers sorted in descending order");

            Console.WriteLine();

            var duplicatesRemoved =
                 from value in ranNum
                 orderby value 
                 select value;

            Display(duplicatesRemoved, "Random Numbers and duplicates removed");



           
               


        }
        public static void Display<T>(IEnumerable<T> results, string header)
        {
            Console.WriteLine("{0}: ", header);
            foreach (T element in results)
                Console.WriteLine(element.ToString());

            Console.WriteLine();
        }
    }
}

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Question by:rcham68
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15 Comments
 
LVL 22

Expert Comment

by:p_davis
ID: 34198772
ranNum = ranNum.Distinct();
0
 

Author Comment

by:rcham68
ID: 34198868
Exactly where does this go?  Here is where I put it but it does not work

 var duplicatesRemoved =
                 from value in ranNum
                 orderby value
                 select ranNum = ranNum.Distinct();
           
            Display(duplicatesRemoved, "Random Numbers and duplicates removed");
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34198890
I would put it right after the for loop.

 for(int count = 0; count <= 29; count++)
            {
                //List<int> ranNum = new List<int>();
                ranNum.Add(randomNumber.Next(1,20));
               
            }
ranNum = ranNum.Distinct();
0
 

Author Comment

by:rcham68
ID: 34198946
Can not put it there it gives me an error explicit conversion exist
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34198982
just cast the distinct to (List<int>)
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34199007
sorry, that doesn't work....
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34199031
this worked

(from num in ranNum
                 select num).Distinct().ToList();
0
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LVL 22

Accepted Solution

by:
p_davis earned 500 total points
ID: 34199034
ranNum = (from num in ranNum
                 select num).Distinct().ToList();
0
 

Author Comment

by:rcham68
ID: 34199093
Thanks
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34199102
np, sorry about the false ones -- wasn't able to test right away
0
 

Author Comment

by:rcham68
ID: 34199143
ranNum = (from num in ranNum
                 select num).Distinct().ToList();

Where did you put this? Every where I put it I am getting a conflict with previous declaration of num
0
 

Author Comment

by:rcham68
ID: 34199150
ranNum = (from num in ranNum
                 select num).Distinct().ToList();

Where did you put this? Every where I put it I am getting a conflict with previous declaration of num
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34199163
num was something that was unique to my testing program -- change the name

ranNum = (from n in ranNum
                 select n).Distinct().ToList();
0
 
LVL 22

Expert Comment

by:p_davis
ID: 34199168
after the for
0
 

Author Comment

by:rcham68
ID: 34199229
Got it working thanks a lot.
0

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