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yccdadmins

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What attribute is an e-mail alias stored in - in Active Directory

When I create an email alias for an end user with an existing AD/Exchange email account - what attributed is that stored in.  I know that "mail" stores the SMTP address and mailnickname stores the part of the email address that precedes the @ in the mail address.

So where is an alias stored?  If I have an email address of kthompson@college.edu then but an email alias of myotheraddress@college.edu then:

Mail = kthompson@college.edu
mailNickName = kthompson

But where is myotheraddress@college.edu stored...?

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tigermatt
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ProxyAddresses will query all email addresses belonging to a user account
It is under 'msExchShadowProxyAddresses' attribute in AD for the user's object and proxyAddresses.
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yccdadmins

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So if I was going to push an end users email alias from an LDAP server to an AD server (in an environment without Exchange) would I push the alias to the msExchShadowProxyAddresses attribute or the proxyAddresses attribute?

Basically I need to place attribute and fill it with the Alias in an AD environment that does not yet have Exchange.
Primary location would be as per Matt's initial comment - proxyAddresses.

You'd want to push it to proxyAddresses.

I'm afraid to say I've never heard of the msExchShadowProxyAddresses attribute - there are various msExchShadow- attributes in the Exchange schema (certainly with Exchange 2010 SP1), but no msExchShadowProxyAddresses. I'm also unsure what these are used for - I've never been able to determine a reason for them being there and no user I've checked has the attributes populated.

proxyAddresses is an AD schema attribute, not an Exchange one, so it will already exist in your schema. You just need to be aware it isn't published automatically to the Global Catalog automatically. This is enabled by either the preparation of the schema for an Exchange installation - or manually, if necessary.

-Matt
This question has been classified as abandoned and is being closed as part of the Cleanup Program. See my comment at the end of the question for more details.