C# new line to break from XML

Hi!

I have one XML document.
I open it with C# LINQ to XML

when I try to replace "\r\n", "\r" or "\n" to "<br />" it is not working.

Some help please.
XDocument xmldata = XDocument.Load(Server.MapPath("content.xml"));

        var quotes = from quote in xmldata.Descendants("row")
                     where (int)quote.Attribute("ID") == 1
                     select new
                     {
                         Content = (string)quote.Attribute("content"),
                     };

        foreach (var quote in quotes)
        {
            content = quote.Content;
        }

        content = content.Replace("\r\n", "<br />").Replace("\n", "<br />").Replace("\r", "<br />");

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kuzmarAsked:
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buraksaricaConnect With a Mentor Commented:
I see. Unfortunately, you cannot preserve newline chars in the attribute values. if you are able to produce this xml in another format, (i mean if YOU are producing this xml) you can wrap the content in an element directly such as:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<data>
<row ID='1'>&quot;Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nullam tempor pretium.  
Aliquam felis quam, sagittis id egestas at, vulputate ut elit.
Nam nec metus libero. Suspendisse sagittis justo at nisi lobortis aliquam&quot;</row>
<row ID='2'>&quot;Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nullam tempor pretium.
Aliquam felis quam, sagittis id egestas at, vulputate ut elit.&quot;</row>
</data>

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Then you can use PreserveWhitespace option of XDocument load method:

XDocument xmldata = XDocument.Load(Server.MapPath("content.xml"),LoadOptions.PreserveWhitespace);

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buraksaricaCommented:
Can you paste or attach an example of Content.xml?
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kuzmarAuthor Commented:
Here it is:
content.xml
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Alfred A.Commented:
You can try this:

content = content.Replace(System.Environment.NewLine, "<br />");
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Alfred A.Commented:
Try the following as well:

string content = Regex.Replace(content, @"\r\n", "<br />",RegexOptions.Multiline);

content = Regex.Replace(content, @"\r", "<br />",RegexOptions.Multiline);

content = Regex.Replace(content, @"\n", "<br />",RegexOptions.Multiline);
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Alfred A.Commented:
Oh I forgot to mention in my previous post that you need to import the System.Text.RegularExpressions library.
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Alfred A.Commented:
You can also try the following:

content = content.Replace("" + (char) 13 + (char) 10, "<br />");

content = content.Replace("" + (char) 13, "<br />");

content = content.Replace("" + (char) 10, "<br />");
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buraksaricaCommented:
Of course, Content = (string)quote.Attribute("content") this line will change to
Content = (string)quote.Value;
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kuzmarAuthor Commented:
Yes. I would have to change how the xml is being presnted. Put content in an element directly.


thx.
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