Solved

# Calculate elapsed business hours - SQL 2008

Posted on 2010-11-24
935 Views
Our business is open 9-5, Monday to Friday.  I am using the SQL function in the attached text file to calculate the elapsed business hours between two datetimes.  The variables are as follows:
@startdate - the start datetime of the period (datetime)
@enddate - the end date of the period (datetime)
@starttime - the start of the business day (vchar(9))
@endtime - the end of the business day (vchar(9))

The function is called with a SQL statement that passes the values of these variables to the function.

Does anyone have any idea how I would go about modifying this function to exclude Saturdays and Sundays from the calculation?

Thanks!
0
Question by:I_play_with_DNA
• 3

LVL 17

Expert Comment

ID: 34208889
FIrst I would ask why the times are separated from the dates.

Create a new combined date/time
e.g.
@startdate = '1/1/2010'
@enddate = ' 1/2/2010'
@starttime = '9:00 am'
@endtime = '12:30 pm'

@newstartdate = '1/1/2010 9:00:00 am'
@newenddate = '1/2/2010 12:30:00 pm'

select datediff(minute,@newstartdate,@newenddate)/60 = the amount of hours spent
0

LVL 17

Expert Comment

ID: 34208928
sorry i shouldnt have thought it was that easy.

select @minutesUsed=datediff(minute,@newstartdate,@newenddate)

Select @minutesUsed=(@minutesUsed-(case when @StartDate<>@EndDate then datediff(day,@startdate,@enddate)*900))

this will remove the after hours minutes between days. You can also do a similar function to check for weekends that have passed.
0

LVL 7

Accepted Solution

rmm2001 earned 167 total points
ID: 34208994
Put in a where DATEPART(weekday, @startdate) NOT IN (1, 7) (1 is sunday...7 is saturday)
0

LVL 7

Assisted Solution

Cboudroz earned 167 total points
ID: 34209882
add this in the where clause:

and DATEPART(dw,DateValue) not in (1,7)
0

LVL 17

Assisted Solution

OriNetworks earned 166 total points
ID: 34210702
Ithe datelart cannot be and otherwise it will evaluate as false for start or end date on weekends and not return a result. You would have to add a case statement with the datepart to subtract those days but this is not good either because it would not calculate weekends in between so oh have to use it in conjunction with a datediff to find out how many weekends are between those dates.
,
0

## Featured Post

Let's review the features of new SQL Server 2012 (Denali CTP3). It listed as below: PERCENT_RANK(): PERCENT_RANK() function will returns the percentage value of rank of the values among its group. PERCENT_RANK() function value always in be…
The Delta outage: 650 cancelled flights, more than 1200 delayed flights, thousands of frustrated customers, tens of millions of dollars in damages – plus untold reputational damage to one of the world’s most trusted airlines. All due to a catastroph…
Using examples as well as descriptions, and references to Books Online, show the documentation available for date manipulation functions and by using a select few of these functions, show how date based data can be manipulated with these functions.
Viewers will learn how to use the INSERT statement to insert data into their tables. It will also introduce the NULL statement, to show them what happens when no value is giving for any given column.