[Last Call] Learn about multicloud storage options and how to improve your company's cloud strategy. Register Now

x
?
Solved

Using Common Table Expression for Recursive Queries

Posted on 2010-11-25
8
Medium Priority
?
502 Views
Last Modified: 2012-05-10
Hi,

I have two tables like this:

-----------------------------------------
Table1
-----------------------------------------
id, table2id, value, date, ....

-----------------------------------------
Table2
-----------------------------------------
id, child, ...

And i use table 2 to populate a treeview (0 is the root level):
id child description
1    0    Level 1
2    1    Level 2a
3    1    Level 2b
4    3    Level 3
5    4    Level 4
...

in the end I get this in the treeview:

Level1
----  Level 2a
----  Level 2b
--------  Level 3
------------  Level 4


Now I want to make a recursive query to get all entries in table1 where the Table1.table2id = Table2.ID, to sum all the Table1.values, plus all the descent nodes available.

Example: I choose the Level 2b I want all results for that and also for Level 3 and Level 4 (or more if exists)


I'm working with Common Table Expression (CTE) for recursive queries, using the WITH keyword, but no goal.

Anyone help me on this?


Thanks!
0
Comment
Question by:jpaulino
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 2
  • 2
8 Comments
 
LVL 60

Assisted Solution

by:HainKurt
HainKurt earned 200 total points
ID: 34214335
0
 
LVL 48

Author Comment

by:jpaulino
ID: 34214400
I have found a lot of links like that, but I'm having problems implementing it :(

I'm trying
0
 
LVL 58

Expert Comment

by:cyberkiwi
ID: 34214454
Not clear what you are after, but this
(1) shows the tree levels
(2) shows the summation of values from table1 for current level + all descendants

/*
create table table1(id int identity, table2id int, value int, date datetime)
insert table1 select 1,2,null
insert table1 select 2,3,null
insert table1 select 3,4,null
insert table1 select 4,5,null
insert table1 select 5,6,null
insert table1 select 5,7,null
insert table1 select 5,8,null
create table table2(id int, child int, description varchar(10))
insert table2 select 1,0,'Level 1'
insert table2 select 2,1,'Level 2a'
insert table2 select 3,1,'Level 2b'
insert table2 select 4,3,'Level 3'
insert table2 select 5,4,'Level 4'
*/
;with cte as (
      select level=1,id,child from table2
     where id=3   --- this is where it all starts, id3=level2b per your question
      union all
      select level+1,a.id,a.child from table2 a
      inner join cte on cte.id=a.child -- parent?! weird naming
), cte2 as (
      select root=id,id,level,sublevel=level+1 from cte
      union all
      select root,a.id,a.level,sublevel+1 from cte a
      inner join cte2 on cte2.id=a.child
)
select replicate('-',min(level)*4-1) + b.description, sum(c.value)
from cte2 a
inner join table2 b on a.root=b.id
inner join table1 c on a.id=c.table2id
group by b.description, root
0
VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

 
LVL 60

Expert Comment

by:HainKurt
ID: 34214456
the one i posted has full script, including table structure, demo data etc...

just you should replace tablename and column names I guess ;)
0
 
LVL 48

Author Comment

by:jpaulino
ID: 34214718
Thanks all for the input!

@cyberkiwi,

I have changed the selection a little for my needs (I need grouped by year, month and sum all the tpl's), but i'm not getting the right results ... i'm making some tests. But it's almost right! ;)

select YEAR(c.data), MONTH(c.data),sum(c.tpl)
from cte2 a
inner join dbo.equipamentos b on a.root=b.id
inner join dbo.mcHistorico c on a.id=c.equipamentoID
GROUP BY  YEAR(c.data), MONTH(c.data)
HAVING YEAR(c.data)=2010

I just need the year+month+sum(table1.tpl)


PS: parent was a wrong translactions for the example ... it has a portuguese name :)
0
 
LVL 58

Accepted Solution

by:
cyberkiwi earned 1800 total points
ID: 34214869
> but i'm not getting the right results

Hold on, you want one sum for a particular record+children?  I thought you wanted something more complicated, on each level, like this:

---Level 2b      30    (4 at level 2b + 26 from all children)
-------Level 3      26    (5 at level 3, plus 21 from level 4)
-----------Level 4      21

It looks like all you want is the result at level 2b, summed up, then broken down again by year, month.  So:


/*
create table mcHistorico(id int identity, equipamentoID int, tpl int, data datetime)
insert mcHistorico select 1,2,'20100101'
insert mcHistorico select 2,3,'20100101'
insert mcHistorico select 3,4,'20100101'
insert mcHistorico select 4,5,'20100101'
insert mcHistorico select 5,6,'20100101'
insert mcHistorico select 5,7,'20100101'
insert mcHistorico select 5,8,'19990101' -- not in 2010
create table equipamentos(id int, child int, description varchar(10))
insert equipamentos select 1,0,'Level 1'
insert equipamentos select 2,1,'Level 2a'
insert equipamentos select 3,1,'Level 2b'
insert equipamentos select 4,3,'Level 3'
insert equipamentos select 5,4,'Level 4'
*/
;with cte as (
     select id,child from equipamentos
     where id=3   --- this is where it all starts, id3=level2b per your question
     union all
     select a.id,a.child from equipamentos a
     inner join cte on cte.id=a.child -- link to previous recursion
)
select YEAR(c.data), MONTH(c.data), SUM(c.tpl)
from cte a
inner join mcHistorico c on a.id=c.equipamentoID
where c.data >= '20100101' and c.data < '20110101'
group by YEAR(c.data), MONTH(c.data)

Open in new window

0
 
LVL 48

Author Comment

by:jpaulino
ID: 34214893
>> Hold on, you want one sum for a particular record+children?

Yes, I just want the sum of all records (parent + childs) for a specific time.

I will test that!

Many thanks ;)
0
 
LVL 48

Author Comment

by:jpaulino
ID: 34218834
Works like a charm :)

Thanks for the great help!
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Ever needed a SQL 2008 Database replicated/mirrored/log shipped on another server but you can't take the downtime inflicted by initial snapshot or disconnect while T-logs are restored or mirror applied? You can use SQL Server Initialize from Backup…
Ever wondered why sometimes your SQL Server is slow or unresponsive with connections spiking up but by the time you go in, all is well? The following article will show you how to install and configure a SQL job that will send you email alerts includ…
Using examples as well as descriptions, and references to Books Online, show the documentation available for date manipulation functions and by using a select few of these functions, show how date based data can be manipulated with these functions.
This videos aims to give the viewer a basic demonstration of how a user can query current session information by using the SYS_CONTEXT function

650 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question