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ZadoFlag for United Kingdom of Great Britain and Northern Ireland

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Add char to each string element

Hi,

I have this:
$Str='test(4)-test(51)-test(9)-test(12)-test(33)-test(4)';
$something_here='';
foreach(explode('-',$Str) as $xx) {
            	$string1=(preg_replace("/\([0-9]\)/", $something_here, $xx));
}
echo $string1;

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So as you can see I need to replace elements inside brackets if there's just one digit, more specifically, I want to add '0' (zero) before this digit. I just need $something_here var, but can't manage with that, please help. Or you can think about different way to do that.
I want this output:
test(04)-test(51)-test(09)-test(12)-test(33)-test(04)

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Thanks.
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pak_slm

Is there Number if test() is fixed, mean  in you string test() present 6 time?
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ASKER

No, it could be any word or number there
i mean count is fixed to 6 or vary.
SOLUTION
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darren-w-
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ASKER

vary, it could be:
asdf(4)-0000000(51)-test1(09)-test2(12)-tesssst(33)-test(4)-12345(1)

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but always hyphen separated and one or two digits in brackets
Avatar of Zado

ASKER

Thanks darren-w-, I changed a bit your script and almost works, it adds zero before one digit, but changes this digit into 'Array' in output, that's the only problem.

function addzero($matches)
{
if (strlen($matches)<6){
$matches= "0".$matches;
}
return '('.$matches.')';
}

foreach(explode('-',$Str) as $xx) {
				$string1=(preg_replace_callback("/\([0-9]\)/", "addzero", $Str));
}
echo $string1;

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It changes this:
test(4)-test(51)-test(9)-test(12)-test(33)-test(4)

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into this:
test(0Array)-test(51)-test(0Array)-test(12)-test(33)-test(0Array)

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but should be this:
test(04)-test(51)-test(09)-test(12)-test(33)-test(04)

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Avatar of Zado

ASKER

Ok, solution is closer here:

function addzero($matches)
{
if (strlen($matches)<6){
$matches= "0".$matches[0];
}
return $matches;
}

foreach(explode('-',$Str) as $xx) {
				$string1=(preg_replace_callback("/\([0-9]\)/", "addzero", $Str));
}
echo $string1;

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Just need to move opening bracket before zero, it gives this output:
      

test0(4)-test(51)-test0(9)-test(12)-test(33)-test0(4)

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SOLUTION
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$Str='test(4)-test(51)-test(9)-test(12)-test(33)-test(4)';
$patterns=array();
$patterns[0] = "/\({1}[0-9]\)/";
$patternsr=array();
$patternsr[0] = "(0\${1}1)";
print preg_replace($patterns,$patternsr,$Str);

returns

test(01)-test(51)-test(01)-test(12)-test(33)-test(01)
oops thats wrong
ASKER CERTIFIED SOLUTION
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Simplified this a little:

<?php
$Str='test(4)-test(51444)-test(9)-test(122)-test(33)-test(1)';
$patterns=array("/\(([0-9])\)/");
$patternsr=array("(0$1)");
print preg_replace($patterns,$patternsr,$Str);
?>

returns: test(04)-test(51444)-test(09)-test(122)-test(33)-test(01)

without callback
Great solution!
More simplify :) :

$Str='test(4)-test(51444)-test(9)-test(122)-test(33)-test(1)';
print preg_replace("/\(([0-9])\)/","(0$1)",$Str);

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ASKER

Thanks for help :-)
Avatar of Zado

ASKER

I found proper solution based on experts comments, I just changed a bit their scripts, but my comment presents actual solution.
Thanks.