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How to grep only ID's

Posted on 2010-11-27
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Last Modified: 2012-08-13
In the  /etc/passwd directory file. there are several users, I just want to locate the primary user  ID's account that starts with 1000 and 1003.

I did the following grep -e "1000" -e "1003" /etc/passwd  but the output also prints 1020 1028 etc.

I just want the 1000 and the 1003 any suggestions.
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Question by:9334gonzalez
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Tintin earned 167 total points
ID: 34222879
awk -F: '$3==1000 || $3==1003 {print}' /etc/passwd
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by:expert_tanmay
expert_tanmay earned 333 total points
ID: 34222880
grep -e '^100[03]' /etc/passwd
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by:expert_tanmay
ID: 34222899
sorry it will be
grep '^100[03]' /etc/passwd

-e is not needed
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by:9334gonzalez
ID: 34222907
grep -e '^100[03]' /etc/passwd


I tried this one and I didn't get any did I missed something
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by:expert_tanmay
expert_tanmay earned 333 total points
ID: 34222922
try without -e
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by:9334gonzalez
ID: 34222956
Thank you,
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