Solved

Uploading Dynamic Photo to Facebook using the API?

Posted on 2010-11-27
8
1,527 Views
Last Modified: 2013-11-19
Hi,

My App trying to uploading a dynamic photo (created by GD + pulling data from MySQL database) so the photos don't statically exist in the directory and for so I get this error :

Fatal error: Uncaught CurlException: 26: failed creating formpost data thrown in

Let's say I'm trying to upload www.mywebsite.com/223.jpg which is dynamic photo you can see it by checking this url directly or calling it as image but If I tried to use it in my Facebook App it wouldn't upload. If I downloaded to photo to my PC then uploaded to my ftp the App would upload it successfully. So I'm sure that my code is working just fine but the problem is with being Dynamic photo (doesn't actually exist in my website ftp).

Please let me know how can I solve this problem.

Code attached:

Thanks for your time.
$photo_details = array(
    'message'=> $message
);
$file = "$_GET[id].png";
$photo_details['image'] = '@/home/username/public_html/files/' . $file;
$upload_photo = $facebook->api('/'.$album_uid.'/photos', 'post', $photo_details);

Open in new window

0
Comment
Question by:Dido123
  • 5
  • 3
8 Comments
 
LVL 109

Expert Comment

by:Ray Paseur
ID: 34225441
Can you please show us a complete code segment that works, like one with an existing file?

CURL error #26 is pretty well understood to be a read error.
http://curl.haxx.se/mail/archive-2003-06/0121.html

Possibly the error arises because (1) the path to the dynamically generated photo is wrong or (2) the file permissions are too restrictive.

I'm also really unsure about this from line 4 of the post above: $file = "$_GET[id].png";

So my instant recommendation is to prepare each of your variables separately so you can visualize them.  Add var_dump($photo_details); after line 5 and see if you're getting the values you expect in that array.  Change line 6 to something more like what is in the code snippet.
// NOT THIS
$upload_photo = $facebook->api('/'.$album_uid.'/photos', 'post', $photo_details);

// INSTEAD THIS
$str = '/' . $album_uid . '/photos';
var_dump($str);
$upload_photo = $facebook->api($str, 'post', $photo_details);

Open in new window

0
 
LVL 109

Expert Comment

by:Ray Paseur
ID: 34225477
Wow, it works and does not bark about anything, so long as the id= parameter is a string.

<?php // RAY_temp_dido123.php
error_reporting(E_ALL);
$file = "$_GET[id].png";
var_dump($file);

Barks about undefined index:
http://www.laprbass.com/RAY_temp_dido123.php

Reasonable output:
http://www.laprbass.com/RAY_temp_dido123.php?id=foo

Strange output:
http://www.laprbass.com/RAY_temp_dido123.php?id[]=foo

I think I would write that line more like this, but it's apparently OK for your app the way it is.
if (!empty($_GET['id']))
{
    $file = $_GET['id'] . '.png';
}
else
{
    $file = 'default.png';
}

Open in new window

0
 

Author Comment

by:Dido123
ID: 34227124
Ray, thanks for your input. I did tried my code and it works if I uploaded 123.png to my ftp. The problem is the photos created dynamically when you call it. So it's not statically found in the ftp. How can I bypass this problem. All I can think of is that the Facebook API needs to find the actual photo in the directory when it tries to upload it. Is there anything that can somehow create a temp photo so the API can find it then it would be deleted after the upload completed or at least something in this way?

Thanks again for your help.
0
DevOps Toolchain Recommendations

Read this Gartner Research Note and discover how your IT organization can automate and optimize DevOps processes using a toolchain architecture.

 
LVL 109

Expert Comment

by:Ray Paseur
ID: 34228483
Without seeing the code, all we would be doing is guessing.  Have you tried the visualization techniques I suggested above?

If your script creates a file and marks it with permissions that make it readable, CURL should be able to read the file.
0
 

Author Comment

by:Dido123
ID: 34244308
After a couple of days researching I came to conclusion that the problem is not in my code. The problem is code above can't read the image since it's dynamic image (requires running the php file which creates it first) so now my solution should be opening the dynamic image and presenting to the code above as static image so it can upload it. The problem is I can't even know where should I start to find my solution. Is fopen or fread might help here?

I really appreciate your help Ray.
0
 
LVL 109

Accepted Solution

by:
Ray Paseur earned 500 total points
ID: 34244970
Let me say this again: "Without seeing the code, all we would be doing is guessing."

Show us how you create the dynamic image.  If you do the following things in order, it WILL work.

1. Create the image
2. Write the image to your server in the file system
3. Set the permissions on the file to allow read and execute.
4. Only after that, treat the file as a static image.

You may want a garbage collection routine just prior to #1 -- it would delete any files that are more than two days old.
0
 

Author Closing Comment

by:Dido123
ID: 34255109
Thank you. Problem solved. That's exactly what I did.

I created temp file for photos I want to upload then I added cron job to empty the temp folder once a day. Thanks again.
0
 
LVL 109

Expert Comment

by:Ray Paseur
ID: 34257979
Bingo!  Thanks for the points - glad it's pointed in the right direction, ~Ray
0

Featured Post

Master Your Team's Linux and Cloud Stack!

The average business loses $13.5M per year to ineffective training (per 1,000 employees). Keep ahead of the competition and combine in-person quality with online cost and flexibility by training with Linux Academy.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Introduction This article is intended for those who are new to PHP error handling (https://www.experts-exchange.com/articles/11769/And-by-the-way-I-am-New-to-PHP.html).  It addresses one of the most common problems that plague beginning PHP develop…
Today, the web development industry is booming, and many people consider it to be their vocation. The question you may be asking yourself is – how do I become a web developer?
The viewer will get a basic understanding of what section 508 compliance can entail, learn about skip navigation links, alt text, transcripts, and font size controls.
Learn how to create flexible layouts using relative units in CSS.  New relative units added in CSS3 include vw(viewports width), vh(viewports height), vmin(minimum of viewports height and width), and vmax (maximum of viewports height and width).

860 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question