[Webinar] Streamline your web hosting managementRegister Today

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 1547
  • Last Modified:

Uploading Dynamic Photo to Facebook using the API?

Hi,

My App trying to uploading a dynamic photo (created by GD + pulling data from MySQL database) so the photos don't statically exist in the directory and for so I get this error :

Fatal error: Uncaught CurlException: 26: failed creating formpost data thrown in

Let's say I'm trying to upload www.mywebsite.com/223.jpg which is dynamic photo you can see it by checking this url directly or calling it as image but If I tried to use it in my Facebook App it wouldn't upload. If I downloaded to photo to my PC then uploaded to my ftp the App would upload it successfully. So I'm sure that my code is working just fine but the problem is with being Dynamic photo (doesn't actually exist in my website ftp).

Please let me know how can I solve this problem.

Code attached:

Thanks for your time.
$photo_details = array(
    'message'=> $message
);
$file = "$_GET[id].png";
$photo_details['image'] = '@/home/username/public_html/files/' . $file;
$upload_photo = $facebook->api('/'.$album_uid.'/photos', 'post', $photo_details);

Open in new window

0
Dido123
Asked:
Dido123
  • 5
  • 3
1 Solution
 
Ray PaseurCommented:
Can you please show us a complete code segment that works, like one with an existing file?

CURL error #26 is pretty well understood to be a read error.
http://curl.haxx.se/mail/archive-2003-06/0121.html

Possibly the error arises because (1) the path to the dynamically generated photo is wrong or (2) the file permissions are too restrictive.

I'm also really unsure about this from line 4 of the post above: $file = "$_GET[id].png";

So my instant recommendation is to prepare each of your variables separately so you can visualize them.  Add var_dump($photo_details); after line 5 and see if you're getting the values you expect in that array.  Change line 6 to something more like what is in the code snippet.
// NOT THIS
$upload_photo = $facebook->api('/'.$album_uid.'/photos', 'post', $photo_details);

// INSTEAD THIS
$str = '/' . $album_uid . '/photos';
var_dump($str);
$upload_photo = $facebook->api($str, 'post', $photo_details);

Open in new window

0
 
Ray PaseurCommented:
Wow, it works and does not bark about anything, so long as the id= parameter is a string.

<?php // RAY_temp_dido123.php
error_reporting(E_ALL);
$file = "$_GET[id].png";
var_dump($file);

Barks about undefined index:
http://www.laprbass.com/RAY_temp_dido123.php

Reasonable output:
http://www.laprbass.com/RAY_temp_dido123.php?id=foo

Strange output:
http://www.laprbass.com/RAY_temp_dido123.php?id[]=foo

I think I would write that line more like this, but it's apparently OK for your app the way it is.
if (!empty($_GET['id']))
{
    $file = $_GET['id'] . '.png';
}
else
{
    $file = 'default.png';
}

Open in new window

0
 
Dido123Author Commented:
Ray, thanks for your input. I did tried my code and it works if I uploaded 123.png to my ftp. The problem is the photos created dynamically when you call it. So it's not statically found in the ftp. How can I bypass this problem. All I can think of is that the Facebook API needs to find the actual photo in the directory when it tries to upload it. Is there anything that can somehow create a temp photo so the API can find it then it would be deleted after the upload completed or at least something in this way?

Thanks again for your help.
0
The new generation of project management tools

With monday.com’s project management tool, you can see what everyone on your team is working in a single glance. Its intuitive dashboards are customizable, so you can create systems that work for you.

 
Ray PaseurCommented:
Without seeing the code, all we would be doing is guessing.  Have you tried the visualization techniques I suggested above?

If your script creates a file and marks it with permissions that make it readable, CURL should be able to read the file.
0
 
Dido123Author Commented:
After a couple of days researching I came to conclusion that the problem is not in my code. The problem is code above can't read the image since it's dynamic image (requires running the php file which creates it first) so now my solution should be opening the dynamic image and presenting to the code above as static image so it can upload it. The problem is I can't even know where should I start to find my solution. Is fopen or fread might help here?

I really appreciate your help Ray.
0
 
Ray PaseurCommented:
Let me say this again: "Without seeing the code, all we would be doing is guessing."

Show us how you create the dynamic image.  If you do the following things in order, it WILL work.

1. Create the image
2. Write the image to your server in the file system
3. Set the permissions on the file to allow read and execute.
4. Only after that, treat the file as a static image.

You may want a garbage collection routine just prior to #1 -- it would delete any files that are more than two days old.
0
 
Dido123Author Commented:
Thank you. Problem solved. That's exactly what I did.

I created temp file for photos I want to upload then I added cron job to empty the temp folder once a day. Thanks again.
0
 
Ray PaseurCommented:
Bingo!  Thanks for the points - glad it's pointed in the right direction, ~Ray
0

Featured Post

The new generation of project management tools

With monday.com’s project management tool, you can see what everyone on your team is working in a single glance. Its intuitive dashboards are customizable, so you can create systems that work for you.

  • 5
  • 3
Tackle projects and never again get stuck behind a technical roadblock.
Join Now