[Last Call] Learn about multicloud storage options and how to improve your company's cloud strategy. Register Now

x
?
Solved

Stuck on an implementation of sum and groupby

Posted on 2010-11-30
7
Medium Priority
?
305 Views
Last Modified: 2012-06-21
Let say i have the following table i.e. .

ID, CLIENTID, TOTAL
1    1   1
2    1   1
3    2   5
4    3   4
5    3   5

I need the to create a sum of TOTAL to output something like

ClientId Total
1 2
2 5
3 9

Can you please confirm how i do this

thanks
Webbo
0
Comment
Question by:Webbo_1980
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 3
7 Comments
 
LVL 6

Accepted Solution

by:
CaptainGiblets earned 2000 total points
ID: 34238870
SELECT clientid, SUM(total) AS Total FROM tablename GROUP BY clientid
0
 

Author Comment

by:Webbo_1980
ID: 34239395
That's the first thing i tried but it doesnt work i.e. get results such as e.g. please see below?

Any suggestions?

770      258
770      10
770      7
770      1709
770      20
770      75
770      18
770      9
793      8
793      14
793      1967
0
 
LVL 6

Expert Comment

by:CaptainGiblets
ID: 34239412
i created a sample table with the information you posted and it works fine, what data types are your columns?
0
NEW Veeam Agent for Microsoft Windows

Backup and recover physical and cloud-based servers and workstations, as well as endpoint devices that belong to remote users. Avoid downtime and data loss quickly and easily for Windows-based physical or public cloud-based workloads!

 

Author Comment

by:Webbo_1980
ID: 34239856
Both are integer and my exact query is...

SELECT Id,  sum(Total) as totalSum from mytable
group by Id, Total
order by Id


0
 
LVL 6

Expert Comment

by:CaptainGiblets
ID: 34239909
you dont want to group by total, only ClientID. also, if you select ID it will not work as each record in ID is unique
0
 

Author Comment

by:Webbo_1980
ID: 34243332
But the problem is this wont give me a total count i.e. if you look at my samples data i.e. client id 1 and 3 you'll see the total values get added not the amount of clientids

Hope this makes sense?
0
 
LVL 15

Expert Comment

by:derekkromm
ID: 34245305
You may need to re-word your question. You stated that you're looking for a combination of Client ID and their Totals.

The query provided by CaptainGiblets does exactly that and his followup is correct.

You need to change the Id in your query to ClientId

SELECT ClientId,  sum(Total) as totalSum from mytable
group by ClientId
order by ClientId
0

Featured Post

Prepare for your VMware VCP6-DCV exam.

Josh Coen and Jason Langer have prepared the latest edition of VCP study guide. Both authors have been working in the IT field for more than a decade, and both hold VMware certifications. This 163-page guide covers all 10 of the exam blueprint sections.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

In this article we will learn how to fix  “Cannot install SQL Server 2014 Service Pack 2: Unable to install windows installer msi file” error ?
What if you have to shut down the entire Citrix infrastructure for hardware maintenance, software upgrades or "the unknown"? I developed this plan for "the unknown" and hope that it helps you as well. This article explains how to properly shut down …
Familiarize people with the process of retrieving data from SQL Server using an Access pass-thru query. Microsoft Access is a very powerful client/server development tool. One of the ways that you can retrieve data from a SQL Server is by using a pa…
This video shows how to set up a shell script to accept a positional parameter when called, pass that to a SQL script, accept the output from the statement back and then manipulate it in the Shell.

650 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question