How do I pass stdout from perl to shell script.

I have a shell script that calls a perl script to decrypt and pulls back a password.  The perl script prints to stdout the decrypted password. (btw when both the scripts are in perl it works, however I have to have a method to do it from shell to perl as well).   The shell script pring this error


/opt/DIFF/fwd_encrypt.sh[177]: =1qaz2wsx:  not found

fyi fwd_encrypt.sh is the shell script name and 1qaz2wsx: is the decrypted password.

from shell script
$password=`/opt/DIFF/decrypt.pl $PAR`
read password


from perl script
print STDOUT $pass;

Again, if I do this perl to perl it works.  If I call /opt/DIFF/decrypt.pl with an ARV, ie

/opt/DIFF/decrypt.pl testfile  --->  it prints out the decrypted password to stdout.  








MatthewFAsked:
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TintinCommented:
The shell script should be

password=`/opt/DIFF/decrypt.pl $PAR`

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or better to use the $() notation

password=$(/opt/DIFF/decrypt.pl $PAR)

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Don't use

read password

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