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John CarneyFlag for United States of America

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Parsing an alphanumeric string and reconstructing and distributing it.

I doubt that I phrased the question properly, but I need a macro or function that will look at a range of cells (say $A$1:$A$600), and when it finds a value like this:


it will parse and reconstruct and distribute the results (in Text to Columns fashion) to other cells like this:

42C    42D    42E    42F

It should ignore substrings that have only one letter after the number so that

12A will produce a blank;
12AC will produce 12A    12B;
3ABC, 5D, 17F, 24B will produce:  3A    3B    3C    17D    17F

The number can be anywhere from 1 to 3 characters, but it will always be at the start of the string.

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Avatar of Travis Hydzik
have a look at the following function, getCells will take a string and return an array of cells.
Try the sub testme to see it in action.

Function getCells(ByRef s As String) As String()

    Dim strTemp As String
    Dim strTempOld As String
    strTempOld = vbNullString
    'find the break between number and letter
    For i = 1 To Len(s)
        strTemp = Mid$(s, i, 1)
        If Not IsNumeric(strTemp) Then
            If LenB(strTempOld) > 0 Then
                If IsNumeric(strTempOld) Then
                    'found the split
                    Exit For
                End If
            End If
        End If
        strTempOld = strTemp
    Next i
    Dim arr() As String
    Dim arrCount As Long
    arrCount = -1
    Dim tempStr1 As String
    Dim tempStr2 As String
    'confirm first are numbers
    tempStr1 = Mid$(s, 1, i - 1)
    If IsNumeric(tempStr1) Then
        tempStr2 = Mid$(s, i)
        If isLetter(tempStr2) Then
            For i = 1 To Len(tempStr2)
                arrCount = arrCount + 1
                ReDim Preserve arr(arrCount)
                arr(arrCount) = tempStr1 & Mid$(tempStr2, i, 1)
            Next i
        End If
    End If
    getCells = arr
End Function

Function isLetter(ByRef s As String) As Boolean
    isLetter = True
    Dim i As Long
    For i = 1 To Len(s)
        If IsNumeric(Mid$(s, i, 1)) Then
            isLetter = False
            Exit For
        End If
    Next i
End Function

Sub testerme()

Dim arr() As String
arr = getCells("42CDEF")

For i = 0 To UBound(arr)
    MsgBox arr(i)
Next i

End Sub

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Avatar of John Carney


Very awesome, thanks!

- John