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PHP preg_replace string question

The following does not seem to work, can you help correct it?

I want to delete "comments"  beginning with    //       UP TO the next <br> OR end of string

preg_replace('@(?<!:)//.*((?=<br( /)*>)|$)@U',  '',  $OrigStringWithComments);

ex:  "ABC //comment1<br>DEF//comment2"

thanks!
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willsherwood
Asked:
willsherwood
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1 Solution
 
Terry WoodsIT GuruCommented:
I changed the criteria for the br tag slightly - try this:
preg_replace('@(?<!:)//.*((?=<br([ /])*>)|$)@U',  '',  $OrigStringWithComments);
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willsherwoodAuthor Commented:
Super thanks - i'm on it, stay tuned momentarily
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willsherwoodAuthor Commented:
sorry still shows  //comments
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Terry WoodsIT GuruCommented:
In fact, the round brackets aren't needed around the bit I changed:
preg_replace('@(?<!:)//.*((?=<br[ /]*>)|$)@U',  '',  $OrigStringWithComments);
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Terry WoodsIT GuruCommented:
Can you post the code you tested with? The example you provided seems to work with my code, and actually even works with your code (but my change was still necessary, I believe)
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Terry WoodsIT GuruCommented:
I mean provide the text that you tested against....
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willsherwoodAuthor Commented:
Sorry for not having narrowed it down further.
(I had of course abstracted in my original example)
The problem centers around additional characters "in" the comment (prior to <br>  or  <br /> )

here is a whittled down test that when   \n is removed, it works.

"  Georgia Island   //input\n<br>Williams ";

is there a way to ignore  \n and other extraneous chars?

thanks for your patience!
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Terry WoodsIT GuruCommented:
I think you need the multiline pattern modifier (m) enabled:

preg_replace('@(?<!:)//.*((?=<br[ /]*>)|$)@Um',  '',  $OrigStringWithComments);
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willsherwoodAuthor Commented:
YAY
perfect.
THANK YOU!
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willsherwoodAuthor Commented:
super!
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