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Checking abort condition in VBA UDF

I am using this statement in a UDF which works fine if the value of st is found in the range A:A.

sabbr = Sheet2.Range("A:A").Find(st, , , xlWhole).Offset(0, 1)

But if the data is not found the code execution is aborted. Can someone show me how to check the presence of st in the range before executing the above statement so that the execution is not aborted.

Dave

Use a range object then test for nothing

ie

Dave

Sub d()
    Dim sabbr As Range
    Set sabbr = Sheet2.Range("A:A").Find(st, , , xlWhole).Offset(0, 1)
    If sabbr Is Nothing Then
        MsgBox sabbr.Value
    Else
        MsgBox "didn''t find it"
    End If
End Sub

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Dave

typo :)

Dim sabbr As Range
    Set sabbr = Sheet2.Range("A:A").Find(st, , , xlWhole)
    If Not sabbr Is Nothing Then
        MsgBox sabbr.Offset(0, 1).Value
    Else
        MsgBox "didn''t find it"
    End If

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Saqib Husain

ASKER

Dave, the assignment is in a udf and not a sub. As soon as the statement is executed the function is aborted. The next statement is not executed.

Saqib

Dave

Saqib

If I run my sample like this then the UDF either gives me the Offset value or a "no find" message

It won't abort

Cheers

Dave

Function Test() As String
    Dim sabbr As Range
    Dim st
    st = "test"
    Set sabbr = Sheets(2).Range("A:A").Find(st, , , xlWhole)
    If Not sabbr Is Nothing Then
        Test = sabbr.Offset(0, 1).Value
    Else
        Test = "didn''t find it"
    End If
End Function


Sub TestMe()
MsgBox Test
End Sub

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Saqib Husain

ASKER

Dave, please take a look at this file UDF-abort.xls

Cell F21 contains refereence to this UDF

Saqib

Dave

Saaib,

What do you want to happen once
HR: MARULA DITCH MR & METER FLUME,OUTLET
is not found?

Cheers

Dave

Rory Archibald

FWIW, you'd be better off passing all ranges as arguments to the function. They should not really be hardcoded in the UDF itself.

Saqib Husain

ASKER

Dave,
If it does not find it in the range I want it to continue with the routine as though the statement was not there.
In fact if the match is found I would like it to exit the routine after assigning the value of sabbr to the function.

Rory,
Yes rory, I agree but for my present assignment there is hardly going to be changes to the ranges.

Saqib

ASKER CERTIFIED SOLUTION

Dave

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Dave

wow, typo 2

Set sabbr1 = Sheet2.Range("A:A").Find(st, , , xlWhole)
If Not sabbr1 Is Nothing Then sabbr = sabbr1.Offset(0, 1)

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Rory Archibald

Saqib,
Doesn't really seem like much of a reason to me, especially as assignments have a tendency to mutate. ;)
Rory

Saqib Husain

ASKER

Dave,
got the point, thanks.

Rory,
I wonder if you misunderstood me. By assignment I meant "the task I am working at" and not "the assignment statement in the question"

Saqib

Dave

Cheers Saqib

Dave

>By assignment I meant "the task I am working at

That's what Rory meant. Inevitable scope creep :)

Saqib Husain

ASKER

Well in that case I would just keep it as it is. There is a lot of work to be done to streamline it. I have been working since a year on it and would need it only for a few months more.

After that... who cares...

;-)