?
Solved

Ordering a List Based on Another List of Values

Posted on 2011-02-12
3
Medium Priority
?
353 Views
Last Modified: 2013-12-17
I have a class called Inventory, with a list of Locations that have a key of what order I want them to be sorted on. I was ASSuming a SortedList would keep the values in order by the keys, but it does not.  Below is the class and the console appplication I'm trying to test it with.
object1 should be sorted => FWBB3B,A2M4,EWM4. The list is thrown back in the same order that it is added.

public class Inventory
    {
        public string InvNumber { get; set; }
        public int Quantity { get; set; }
        public string Description { get; set; }
                
        SortedList<int,string> Location = new SortedList<int, string>();
        SortedList<int,string> LocationList = new SortedList<int,string>()
        {
             {1,"C5"},{2,"FW"},{3,"A1"},{4,"A2"},{5,"B1"},{6,"B2"},{7,"EW"},{8,"C1"},{9,"C2"},{10,"C3"},{11,"C4"},{12,"Howie"},{13,"MA"},
             {14,"D1"},{15,"D2"},{16,"D3"},{17,"D4"},{18,"D5"},{19,"E1"},{20,"E2"},{21,"F1"},{22,"F2"},{23,"GB"},{24,"G1"},{25,"G2"},
             {26,"BW"},{27,"G3"},{28,"G4"},{29,"H1"},{30,"H2"},{31,"H3"},{32,"H4"},{33,"I1"},{34,"I2"},{35,"J1"},{36,"J2"},{37,"K1"},
             {38,"K2"},{39,"L1"},{40,"L2"},{41,"L3"},{42,"L4"},{43,"M1"},{44,"M2"},{45,"M3"},{46,"M4"},{47,"N1"},{48,"N2"},{49,"N3"},
             {50,"N4"},{51,"NW"},{52,"O1"},{53,"O2"},{54,"O3"},{55,"O4"},{56,"SW"},{57,"BRP"}
        };

        public Inventory()
        {
            this.InvNumber = "";
            this.Quantity = 0;
            this.Description = "";
        }

        public Inventory(string invNumValue, string quantityValue, string locationValue, string deascriptionValue)
        {
            this.InvNumber = invNumValue;
            this.Quantity = Int16.Parse(quantityValue);
            BuildLocationList(locationValue);
            this.Description = deascriptionValue;

        }

        private void BuildLocationList(string locationValue)
        {
            string[] templocations = locationValue.Split(',');
            //SortedDictionary<int,string> tempdict = new SortedDictionary<int, string>();

            foreach (string s in templocations)
            {
                foreach (KeyValuePair<int, string> kvp in LocationList)
                {
                    if (s.Trim().StartsWith(kvp.Value))
                    {
                        Location.Add(kvp.Key, s.Trim());
                    }
                }

            }
            //Location.Sort(delegate(int x, int y) { return x.CompareTo(y); });

         }

     }

Open in new window

class Program
    {
        static void Main(string[] args)
        {
            Inventory object1 = new Inventory("80401-W","1","EWM4,A2M4,FWBB3B","AJDHJKAHSDJKHASDJKH");
            Inventory object2 = new Inventory("80401-E", "10", "B1K4,O2PP3B,A2J3", "AJDHJKAHSDJKHASDJKH");

            foreach (string s in object1.Location)
            {
                Console.WriteLine(s);
            }
            

            Console.ReadLine();

            
        }
    }

Open in new window

0
Comment
Question by:frtools
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
3 Comments
 
LVL 37

Accepted Solution

by:
TommySzalapski earned 2000 total points
ID: 34879624
It's because you are pulling them out as strings, not key/value pairs. Mine worked great when I changed the code in program to
      foreach (KeyValuePair<int, string> s in object1.Location)
      {
        Console.WriteLine(s.Value);
      }

Open in new window

0
 
LVL 37

Expert Comment

by:TommySzalapski
ID: 34879646
I also had to make Location public to get it to compile
0
 

Author Closing Comment

by:frtools
ID: 34879860
Perfect, never thought that the testing application was feeding back wrong information.
0

Featured Post

Will your db performance match your db growth?

In Percona’s white paper “Performance at Scale: Keeping Your Database on Its Toes,” we take a high-level approach to what you need to think about when planning for database scalability.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Iteration: Iteration is repetition of a process. A student who goes to school repeats the process of going to school everyday until graduation. We go to grocery store at least once or twice a month to buy products. We repeat this process every mont…
The article shows the basic steps of integrating an HTML theme template into an ASP.NET MVC project
I've attached the XLSM Excel spreadsheet I used in the video and also text files containing the macros used below. https://filedb.experts-exchange.com/incoming/2017/03_w12/1151775/Permutations.txt https://filedb.experts-exchange.com/incoming/201…
In this video, Percona Director of Solution Engineering Jon Tobin discusses the function and features of Percona Server for MongoDB. How Percona can help Percona can help you determine if Percona Server for MongoDB is the right solution for …
Suggested Courses

752 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question