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koossa

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Populate table with dates.

I have for example a name 'John' and a start date '1990-01-01' and an end date '2011-01-01'

My destination table is [Name], [Date]

How would I insert an entry for each day in the destination using a single query?.


Example

[NAME]      [DATE]
John          1900-01-01
John          1900-01-02
John          1900-01-03
John          1900-01-04
John          1900-01-05
....................................
....................................
....................................
John          2010-12-30
John          2010-12-31
John          2011-01-01


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Avatar of mkobrin
mkobrin

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Avatar of Alpesh Patel
Hi,

Use code block to insert date from start date to end date. or use cursor. Run till end date and insert data in table.
Koossa,

the easy way is to create a small loop to create an entry

I've made a small Code snippit for you .
You can use it to create a Stored procedure, or you can change it to run Once.

Regards
Poor beggar


create table #Tmp
(
	[Name]  varchar(255),
	[Date] datetime
)


declare @start datetime;
declare @end datetime;
declare @Name varchar(255);

set @start = '1990-01-01' 
set @end = '2011-01-01'
set @name = 'John'


declare @LoopCounter int
declare @loops int
set @loops = convert(int,@end - @start)
set @LoopCounter=0

while @LoopCounter<=@loops
begin
	insert into #Tmp select @Name, dateadd(day,@LoopCounter,@start) 
	set @LoopCounter = @LoopCounter +1 
end 

select * from #Tmp
drop table #Tmp

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;WITH CTE
AS
(
	SELECT CAST('1900-01-01' AS DATETIME) AS GenDate 
	UNION ALL
	SELECT DATEADD(day,1,GENDATE) FROM CTE WHERE GENDATE < '2011-01-01'
)

SELECT * INTO DATETABLE FROM CTE
option (MAXRECURSION   0);			
	

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