Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 800
  • Last Modified:

Complex sql query

Hi,

I am stuck with this crystal report summary

This is what my table looks like

memno          bookid
    1                    11
    1                    12
    1                    13
   
    2                    14
    2                    15
   
    15                  16

    18                  17
    18                  18
    18                  19

From that table I get an SQL query

I want to get result like this

memno       bookcount      booklist               memno1-10   memno11-20    book1-10   book11-20
    1                       3             11, 12, 13                2                        2                     5                    4
    2                       2             14,15                       2                        2                     5                    4
    15                     1             16                            2                        2                     5                    4
    15                     3             17, 18, 19                2                        2                     5                    4

And do case statement

for count based on the member group

for member 1 - 10 = there are 2 members
for member 11 - 2 = there are 2 members

for member 1 - 10 there are 5 books
for member 11 - 2 = there are 4 books

I manage to display the result below using the attached query

------------------------------------------------
memno          bookcount      booklist                
    1                       3             11, 12, 13  
    2                       2             14,15  
    15                     1             16
    15                     3             17, 18, 19
------------------------------------------------

But I cant get the sql sum(count) statement to display what I wanted to


Thank You

SELECT
   t1.memno,
   BookCount = (SELECT COUNT(*)
				  FROM BookTable t2
			      WHERE t1.memno = t2.memno),
   
   BookList = substring((SELECT (',' + bookid )
                           FROM BookTable t2
                           WHERE t1.memno = t2.memno
                           ORDER BY 
                              memno,
                              bookid
                           FOR XML PATH('')
                          ), 3, 1000 )   
FROM BookTable t1                        
GROUP BY memno ORDER BY memno

Open in new window

0
elmbrook
Asked:
elmbrook
1 Solution
 
mlmccCommented:
Do you want SQL solution or a report based solution?

mlmcc
0
 
elmbrookAuthor Commented:
Hi mlmcc

Report based solution would be the best I think
Because I already get the fields I want

Except for the summary,

What I want is a summary like this at the bottom of the report

Member Group          memberCount                 TotalBookCount
1 - 10                        there are 2 members      there are 5 books
11 - 2                         there are 2 members      there are 4 books

Thank You








0
 
LowfatspreadCommented:
JUST CROSS JOIN AND pivot
sELECT MEMNO,BOOKCOUNT,BOOKLIST
      ,[memno1-10],[memno11-20],[book1-10],[book11-20]
  FROM (
SELECT
   t1.memno,
   BookCount = (SELECT COUNT(*)
				  FROM BookTable t2
			      WHERE t1.memno = t2.memno),
   
   BookList = substring((SELECT (',' + bookid )
                           FROM BookTable t2
                           WHERE t1.memno = t2.memno
                           ORDER BY 
                              memno,
                              bookid
                           FOR XML PATH('')
                          ), 3, 1000 )   
FROM BookTable t1                        
GROUP BY memno 
) AS a
CROSS jOIN (
select [memno1-10],[memno11-20],[book1-10],[book11-20]
  from (select case when memno between 1 and 10 then 'memno1-10' 
            when memno betweeb 11 and 20 then 'memno11-20'
          end as Memgrp,MEMNO
         FROM BookTable) AS X1
  PIVOT (COUNT(DISTINCT MEMNO) FOR MEMGRP IN ([memno1-10],[memno11-20])) AS P1
  CROSS jOIN
        (select case when memno between 1 and 10 then 'BOOK1-10' 
            when memno betweeb 11 and 20 then 'BOOK11-20'
          end as Memgrp,bOOKID
         FROM BookTable) AS X2
  PIVOT (COUNT(BOOKID) FOR MEMGRP IN ([book1-10],[book11-20])) AS P2
) AS b
ORDER BY 1

Open in new window

0
Veeam Disaster Recovery in Microsoft Azure

Veeam PN for Microsoft Azure is a FREE solution designed to simplify and automate the setup of a DR site in Microsoft Azure using lightweight software-defined networking. It reduces the complexity of VPN deployments and is designed for businesses of ALL sizes.

 
elmbrookAuthor Commented:
Hi Lowfatspread,

I cant get the query working
My table only have 2 fields memno and bookid

While [memno1-10],[memno11-20],[book1-10],[book11-20] is aliases

And I am getting error in there with invalid column


Thank You
0
 
LowfatspreadCommented:
POST THE ERROR MESSAGE
0
 
LowfatspreadCommented:
try this
sELECT MEMNO,BOOKCOUNT,BOOKLIST
      ,[memno1-10],[memno11-20],[book1-10],[book11-20]
  FROM ( select memno,bookcount
               ,BookList = substring((SELECT (',' + bookid )
                                        FROM BookTable t2
                                       WHERE t1.memno = t2.memno
                                       ORDER BY memno,bookid
                                         FOR XML PATH('')
                                      ), 3, 1000 )   
          from (SELECT memno, count(*) as Bookcount
                  FROM BookTable                         
                 GROUP BY memno) as T1
       ) AS a
CROSS jOIN (
select [memno1-10],[memno11-20],[book1-10],[book11-20]
  from (select case when memno between 1 and 10 then 'memno1-10' 
            when memno between 11 and 20 then 'memno11-20'
          end as Memgrp,MEMNO
         FROM BookTable) AS X1
  PIVOT (COUNT(DISTINCT MEMNO) FOR MEMGRP IN ([memno1-10],[memno11-20])) AS P1
  CROSS jOIN
        (select case when memno between 1 and 10 then 'BOOK1-10' 
            when memno between 11 and 20 then 'BOOK11-20'
          end as Memgrp,bOOKID
         FROM BookTable) AS X2
  PIVOT (COUNT(BOOKID) FOR MEMGRP IN ([book1-10],[book11-20])) AS P2
) AS b
ORDER BY 1

Open in new window

0
 
elmbrookAuthor Commented:
Hi Lowfatspread,

I attached the screenshot with the error.
Please advise if there are mistakes.

I rename [memno1-10],[memno11-20],[book1-10],[book11-20]  to
totalmemno1 , totalmemno2, totalbook1 and totalbook2 so it is easier to read


Thank You


sql-error.bmp
0
 
LowfatspreadCommented:
ok give this a whirl
sELECT MEMNO,BOOKCOUNT,BOOKLIST
      ,[totalmemno1],[totalmemno2],[totalbook1],[totalbook2]
  FROM ( select memno,bookcount
               ,BookList = substring((SELECT (',' + bookid )
                                        FROM BookTable t2
                                       WHERE t1.memno = t2.memno
                                       ORDER BY memno,bookid
                                         FOR XML PATH('')
                                      ), 3, 1000 )   
          from (SELECT memno, count(*) as Bookcount
                  FROM BookTable                         
                 GROUP BY memno) as T1
       ) AS a
CROSS jOIN (
select [totalmemno1],[totalmemno2],[totalbook1],[totalbook2]
  from (select distinct case when memno between 1 and 10 then 'totalmemno1' 
            when memno between 11 and 20 then 'totalmemno2'
          end as Memgrp,MEMNO
         FROM BookTable) AS X1
  PIVOT (COUNT(MEMNO) FOR MEMGRP IN ([totalmemno1],[totalmemno2])) AS P1
  CROSS jOIN
        (select case when memno between 1 and 10 then 'totalBOOK1' 
            when memno between 11 and 20 then 'totalBOOK2'
          end as Memgrp,bOOKID
         FROM BookTable) AS X2
  PIVOT (COUNT(BOOKID) FOR MEMGRP IN ([totalbook1],[totalbook2])) AS P2
) AS b
ORDER BY 1

Open in new window

0
 
ZtinelCommented:
Why do pivot when you can do this:
SELECT
   t1.memno,
   BookCount = (SELECT COUNT(*)
                          FROM BookTable t2
                        WHERE t1.memno = t2.memno),
   
   BookList = substring((SELECT (',' + bookid )
                           FROM BookTable t2
                           WHERE t1.memno = t2.memno
                           ORDER BY
                              memno,
                              bookid
                           FOR XML PATH('')
                          ), 3, 1000 ),
   [memno1-10] = (select count(distinct memno)
                    from #BookTable where memno<= 10),
   [memno11-20] = (select count(distinct mem)
            from #BookTable where memno> 10 ),
   [book1-10] = (select count(bookid)
            from #BookTable where memno<= 10 ),
   [book1-10] = (select count(bookid)
            from #BookTable where memno> 10 )  
FROM BookTable t1                        
GROUP BY memno ORDER BY memno
0

Featured Post

Fill in the form and get your FREE NFR key NOW!

Veeam is happy to provide a FREE NFR server license to certified engineers, trainers, and bloggers.  It allows for the non‑production use of Veeam Agent for Microsoft Windows. This license is valid for five workstations and two servers.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now