Join query on access

Hi there,
In access i have a table A and a table B.
A.asid is the primary key and B.asid is the foreign key.

I need the following set of results
I need
all records of A that do not appear in B OR appear in B and have B.smth = 1
moreover i need the following to stand true
A.check1 = 1 and
A.check2 = 1 and
A.check3 is not null

Can you help me with the query???
Thanks
ioustinos_sarrisAsked:
Who is Participating?
 
HainKurtConnect With a Mentor Sr. System AnalystCommented:
sum(iif(b_smth=0,1,0))>0)

if b_smth=0 then return 1 else 0
then we sum all these
then if this sum is >1 it means there is at least one record that b_stmt is 0

rec b_stmth iif(b_smth=0,1,0))>0)
A    0            1
A    1            0
A    1            0
B    0            1
B    1            0
C    1            0
C    1            0

sum (iif(b_smth=0,1,0))
A     1  >>> we do not want this record
B     1  >>> we do not want this record
C     0
0
 
Shaun KlineLead Software EngineerCommented:
Try this:

Select * from [table a] as A
    left outer join [table b] as B on A.asid = B.asid
where a.check1 = 1
  and a.check2 = 1
  and a.check3 is not null
  and (b.asid is null or b.smth = 1)
0
 
HainKurtSr. System AnalystCommented:
try this:

select a.*, b.asisid as b_asisid from (
select * from a left join b on a.asisid= b.asisid
) x where ((b_asisid is null) or (b_asisid is not null and b.smth=1))
and A.check1 = 1 and
and A.check2 = 1 and
and A.check3 is not null

0
Free Tool: Path Explorer

An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

 
ioustinos_sarrisAuthor Commented:
@shaun kline

I used your query and it seems almost perfect.
I have two problems which probably occur due to me giving wrong specification

The relation A-B is one to many.
A) If at least one b.smth for one record of A is 0 then i do not want that A record in the results set

B) If one record of A has two instances on B with b.smth = 1 then i need only one appearance of A in the results set

Could you help me futhermore please?
0
 
HainKurtSr. System AnalystCommented:
try this( this query will not produce duplicate a record):

Select * from [table a] as a
where a.check1 = 1
  and a.check2 = 1
  and a.check3 is not null
  and a.asid not in (select asid from B group by asid having sum(iif(b_smth=0,1,0))>0)
0
 
ioustinos_sarrisAuthor Commented:
@HainKurt

I do not understand the syntax iif(b_smth=0,1,0))>0)

B.smth actually takes the value "trial" and "regular" not 0 and 1
Could you syntax it for me once again because every effort of mine produced a syntax error??
Will this query produce exactly what i needed???
0
 
Shaun KlineLead Software EngineerCommented:
If you only want the record from table a without any data from table b, try this:

select *
from [table a]
where check1 = 1
  and check2 = 1
  and check3 is not null
  and asid not in (select asid from [table b] where smth = 0)

If you want values from one record in table b, you will need to let us know what field (including data type) will make the distinction and whether it should be the first (min) or last (max).
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.