XSL: side tree navigation (IF child node is open THEN make its parent node RED font)

I'm making changes to the LHS navigation to this site: http://www.thelearningfederation.edu.au/for_jurisdictions/collaborative_networks/collaborative_networks.html

Believe I need to add this extra code somewhere between lines 388-399 of the untitled.xsl file attached.

 
<li>
              <xsl:choose>
               <!-- <xsl:when test="position() = 1"></xsl:when>-->
               <!-- IF child node is open THEN make its parent node BOLD -->
                <xsl:when test="@id = $assetID">
                  <a href="{$TopLinkURL}" class="{$selected}"><b><xsl:value-of select="@title" /></b></a>
                </xsl:when>
                <xsl:otherwise>
                  <a href="{$TopLinkURL}" class="{$selected}"><xsl:value-of select="@title" /></a>
                </xsl:otherwise>
              </xsl:choose>

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 untitled.xsl
jeremyllAsked:
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Geert BormansConnect With a Mentor Information ArchitectCommented:
well, no it does not and yes it does a little.

I now understand what you are after (that was absolutely not clear from the first question)

but now it still is a puzzle how you know that a child node is open?

I took the naieve approach thinking that the functionality you needed was explained in the comment from the original code,
as you are trying to change an existing code-base
... so it is not.

I need to know
- how the original code behaves (the one you posted)
- how the source XML looks like
- how we know what "open" means in terms of parameter values, element or attribute values
- how much of the code you sent is original and what you have changed so far

I can't reconstruct what you have with the information you have given sofar
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Geert BormansInformation ArchitectCommented:
seems like all you need to do is replace this (line 394)
                  <a href="{$TopLinkURL}" class="{$selected}"><b><xsl:value-of select="@title" /></b></a>
into this
                  <a href="{$TopLinkURL}" class="{$selected}"><span style="color:red;"><xsl:value-of select="@title" /></span></a>

you might also need to change the CSS a little to make sure that the blue color of the link does not take precedence

and if you still need it bold, leave the <b> tags intact and wrap the <span> around it (or inside it)

I hope this is waht you need, and if it is not, explain in detail what you need because your question is VERY unclear
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jeremyllAuthor Commented:
Thanks Gertone, that's not exactly what I'm after.

I need all the navigation items to be BOLD/RED when child node is open THEN make ITS parent node BOLD/RED. So when navigation tree is opened at three levels deep, there should be 3 navigation items bold/red. If it's four levels deep, then 4 items bold/red, etc.

I hope this explains my question better.
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jeremyllAuthor Commented:
The image is an example of how I would like the navigation styling to behave.

In the example image the parent node of 'design and development overview' (3rd level) is 'Guide to learning object development' (2nd level) which is the child node of 'Resource process development' (1st level.

hope this is clearer.

The only code I've changed so far is those line 388-299 in the code embeded in the first post.

 example
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Geert BormansInformation ArchitectCommented:
can you also post the source XML?
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jeremyllAuthor Commented:
I'm new to xml/xsl. And not exactly sure what you mean by the XML. Is this the XML output that is produced by the xs parsed?

I have a good feeling which file you want, but the file is 7MB
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jeremyllAuthor Commented:
Problem got too complicated to explain
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Geert BormansInformation ArchitectCommented:
I think it got indeed.
You can still zip the file (yes, I likely need the 7MB file, but you could strip it down to essentials)
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