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awk question

Posted on 2011-02-16
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Last Modified: 2012-05-11
Hi all

    I have to extract field 2 from a /etc/shadow file  were the field
Hash filed doesn’t begin with  ($) character  I know how to
Extract the fiel in question bu not when I want to exlude
All the lines were filed 2 begins with $ in the example
Below I want only users 4 5 6

cat /etc/shadow | awk   'BEGIN {FS=":"} {print $1 ,$2}'

user1: $1$fzNYJ5hW$47JQKHHa7uYHH8SqpUwH3/
user2: $1$HjJNobM9$ZHeda26/JYXJlCUgkehW60
user3: $1$XivDPT4M$fHVwDz3UR3cIBfYaEA8jT1
user4:1VI1N2Yi3R3EI:14495::::::
user5:qcD/yKtWISo12:13451::::::
user6:T4oMaMD.tBqOs:11426::::::
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Question by:d_asselin
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4 Comments
 
LVL 16

Expert Comment

by:jmatix
ID: 34907970
cat /etc/shadow | awk   'BEGIN {FS=":"} index($2, "$") {print $1 ,$2}'
0
 

Author Comment

by:d_asselin
ID: 34908018
Not there yet

   I need the lines that field $2 doesn’t begin with $
With this line I get all the lines that begin with $

0
 
LVL 16

Accepted Solution

by:
jmatix earned 500 total points
ID: 34908085
Sorry,

cat /etc/shadow | awk   'BEGIN {FS=":"} !index($2, "$") {print $1 ,$2}'
0
 

Author Closing Comment

by:d_asselin
ID: 34908132
This is perfect
 Dan
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