Quick sql help

what does this mean "week of the month"?

check this

http://weblogs.sqlteam.com/brettk/archive/2005/06/02/5528.aspx

maybe this

DATEPART(DAY, GETDATE() - 1) / 7 + 1 AS theWeekWithinMonth

not sure if you want the week of the curent month or the number of the current week.

the code Hankurt gave you will give you the number of the week in the current month, this will give you the number of the current week

SELECT DATEPART( wk, GETDATE() )

or maybe this

DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date))

the one i posted above @ 34908746 gives you the diff between weeknumber of a date and the weeknumber of 1st day of that date

@date = 2011-02-16 -- current date
DatePart(ww, @date) = 8 -- week number of current date
dateadd(day, -datepart(day, @date)+1, @date) = 2011-02-01 -- first day of current date
DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) = 6 - week number of above

and the differnce is what you want I guess:

8-6 = 2

or maybe +1 is what you want

DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) +1

I am lost...
how would tackle years in this one?

ok, summary:

this is what you want

DatePart(ww, date) - DATEPART(ww, dateadd(day, -datepart(day, date)+1, date)) +1
or
DATEPART(DAY, date- 1) / 7 + 1

here is the implemenattion in your query:

select model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date) as varchar(10)) + '/' +  cast(DatePart(ww, date) as varchar(10)) as date1, DatePart(ww, date)  as week1, count(MAN) as count1, DATEPART(DAY, date- 1) / 7 + 1 week_of_month
from table
where DatePart(year, date) >= 2010
group by model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date)  as varchar(10))+ '/' +  cast(DatePart(ww, date) as varchar(10)) , DatePart(ww, date), DATEPART(DAY, date- 1) / 7 + 1

if this is not what you want, try the other option

Try this.  I'm not at work so cannot verify but should be close.  

Declare
   @Date         datetime

-- Get first day of the week that Jan 1st falls in
Set @Date = select DATEADD(wk, DATEDIFF(wk,0,’01-Jan-2011’), 0);


While datepart(year, @Date) = ‘2011’
     BEGIN
	Select @Start_Date, datepart(week, @Date)

         -- add one week
         SET @Date = DateAdd(day, 7, @Date)
     END

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Sorry -- a typo above.  Use this instead.

Declare
   @Date         datetime

-- Get first day of the week that Jan 1st falls in
Set @Date = select DATEADD(wk, DATEDIFF(wk,0,’01-Jan-2011’), 0);


While datepart(year, @Date) = ‘2011’
     BEGIN
	Select @Date, datepart(week, @Date)

         -- add one week
         SET @Date = DateAdd(day, 7, @Date)
     END

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First of all thanks alot for help. But may be I need a little more :)
DATEPART(DAY, date- 1) / 7 + 1 as week_of_month --- how does this work?

(7-1)/7+1 - 1.857 = 2 ----

when I see it against record. I see,

test      2010/1/2           14        1

according to my understanding it should have been showing

test      2010/1/2           14        3

Isnt it?

its kool. as I can see and work out what to add.
But may be you can post further scomments if you like.

Thanks

Here I put all logic discussed here

I prefer this one because it looks more logical

DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) +1

check this query, wom3 is more accurate... if you can define what is the first week of a month, then we can write the qry... for now you can use wom3 :)

(change -5 to any number to test that day, +/- any number)

declare @date datetime = getdate()-5;

select @date date, 
DatePart(ww, @date) ww_date,
DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) ww_1stDayofmonth,
DATEPART(DAY, @date - 1) / 7 + 1 wom1,
DATEPART(DAY, @date) / 7 + 1 wom2,
DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) +1 wom3

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