Solved

Quick sql help

Posted on 2011-02-16
14
183 Views
Last Modified: 2012-05-11
Hi,
Please have a look at the sql below.
How can I get the week of the month in this sql?
I.e weeks as 1, 2 ,3 ,4 for every month may be in  another column

THanks
select model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date) as varchar(10)) + '/' +  cast(DatePart(ww, date) as varchar(10)) as date1, DatePart(ww, date)  as week1, count(MAN) as count1
from table
where DatePart(year, date) >= 2010
group by model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date)  as varchar(10))+ '/' +  cast(DatePart(ww, date) as varchar(10)) , DatePart(ww, date)

Open in new window

0
Comment
Question by:SameerMirza
  • 8
  • 3
  • 2
  • +1
14 Comments
 
LVL 51

Expert Comment

by:HainKurt
ID: 34908644
what does this mean "week of the month"?
0
 
LVL 51

Expert Comment

by:HainKurt
ID: 34908647
0
 
LVL 51

Expert Comment

by:HainKurt
ID: 34908654
maybe this

DATEPART(DAY, GETDATE() - 1) / 7 + 1 AS theWeekWithinMonth
0
 
LVL 3

Expert Comment

by:QuinnDester
ID: 34908714
not sure if you want the week of the curent month or the number of the current week.

the code Hankurt gave you will give you the number of the week in the current month, this will give you the number of the current week

SELECT DATEPART( wk, GETDATE() )
0
 
LVL 51

Expert Comment

by:HainKurt
ID: 34908746
or maybe this

DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date))
0
 
LVL 51

Expert Comment

by:HainKurt
ID: 34908832
the one i posted above @ 34908746 gives you the diff between weeknumber of a date and the weeknumber of 1st day of that date

@date = 2011-02-16 -- current date
DatePart(ww, @date) = 8 -- week number of current date
dateadd(day, -datepart(day, @date)+1, @date) = 2011-02-01 -- first day of current date
DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) = 6 - week number of above

and the differnce is what you want I guess:

8-6 = 2

or maybe +1 is what you want

DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) +1


0
 

Author Comment

by:SameerMirza
ID: 34908885
I am lost...
how would tackle years in this one?
0
What is SQL Server and how does it work?

The purpose of this paper is to provide you background on SQL Server. It’s your self-study guide for learning fundamentals. It includes both the history of SQL and its technical basics. Concepts and definitions will form the solid foundation of your future DBA expertise.

 
LVL 51

Expert Comment

by:HainKurt
ID: 34908926
ok, summary:

this is what you want

DatePart(ww, date) - DATEPART(ww, dateadd(day, -datepart(day, date)+1, date)) +1
or
DATEPART(DAY, date- 1) / 7 + 1

here is the implemenattion in your query:

select model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date) as varchar(10)) + '/' +  cast(DatePart(ww, date) as varchar(10)) as date1, DatePart(ww, date)  as week1, count(MAN) as count1, DATEPART(DAY, date- 1) / 7 + 1 week_of_month
from table
where DatePart(year, date) >= 2010
group by model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date)  as varchar(10))+ '/' +  cast(DatePart(ww, date) as varchar(10)) , DatePart(ww, date), DATEPART(DAY, date- 1) / 7 + 1

if this is not what you want, try the other option
0
 
LVL 2

Expert Comment

by:Eric3141
ID: 34908946
Try this.  I'm not at work so cannot verify but should be close.  







Declare
   @Date         datetime

-- Get first day of the week that Jan 1st falls in
Set @Date = select DATEADD(wk, DATEDIFF(wk,0,’01-Jan-2011’), 0);


While datepart(year, @Date) = ‘2011’
     BEGIN
	Select @Start_Date, datepart(week, @Date)

         -- add one week
         SET @Date = DateAdd(day, 7, @Date)
     END

Open in new window

0
 
LVL 2

Expert Comment

by:Eric3141
ID: 34908959
Sorry -- a typo above.  Use this instead.
Declare
   @Date         datetime

-- Get first day of the week that Jan 1st falls in
Set @Date = select DATEADD(wk, DATEDIFF(wk,0,’01-Jan-2011’), 0);


While datepart(year, @Date) = ‘2011’
     BEGIN
	Select @Date, datepart(week, @Date)

         -- add one week
         SET @Date = DateAdd(day, 7, @Date)
     END

Open in new window

0
 
LVL 51

Accepted Solution

by:
HainKurt earned 500 total points
ID: 34908964
you can delete

"DatePart(ww, date)  as week1," from select and delete "DatePart(ww, date)," from group by

select model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date) as varchar(10)) + '/' +  cast(DatePart(ww, date) as varchar(10)) as date1, count(MAN) as count1, DATEPART(DAY, date- 1) / 7 + 1 week_of_month
from table
where DatePart(year, date) >= 2010
group by model, cast(DatePart(year, date) as varchar(10)) + '/' + cast( DatePart(quarter, date)  as varchar(10))+ '/' +  cast(DatePart(ww, date) as varchar(10)) , DATEPART(DAY, date- 1) / 7 + 1

if you dont need that column at all after adding week_of_month
0
 

Author Comment

by:SameerMirza
ID: 34909147
First of all thanks alot for help. But may be I need a little more :)
DATEPART(DAY, date- 1) / 7 + 1 as week_of_month --- how does this work?

(7-1)/7+1 - 1.857 = 2 ----

when I see it against record. I see,

test      2010/1/2           14        1

according to my understanding it should have been showing

test      2010/1/2           14        3

Isnt it?
0
 

Author Closing Comment

by:SameerMirza
ID: 34909251
its kool. as I can see and work out what to add.
But may be you can post further scomments if you like.

Thanks
0
 
LVL 51

Expert Comment

by:HainKurt
ID: 34909570
Here I put all logic discussed here

I prefer this one because it looks more logical

DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) +1

check this query, wom3 is more accurate... if you can define what is the first week of a month, then we can write the qry... for now you can use wom3 :)

(change -5 to any number to test that day, +/- any number)
declare @date datetime = getdate()-5;

select @date date, 
DatePart(ww, @date) ww_date,
DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) ww_1stDayofmonth,
DATEPART(DAY, @date - 1) / 7 + 1 wom1,
DATEPART(DAY, @date) / 7 + 1 wom2,
DatePart(ww, @date) - DATEPART(ww, dateadd(day, -datepart(day, @date)+1, @date)) +1 wom3

Open in new window

0

Featured Post

How to improve team productivity

Quip adds documents, spreadsheets, and tasklists to your Slack experience
- Elevate ideas to Quip docs
- Share Quip docs in Slack
- Get notified of changes to your docs
- Available on iOS/Android/Desktop/Web
- Online/Offline

Join & Write a Comment

If you having speed problem in loading SQL Server Management Studio, try to uncheck these options in your internet browser (IE -> Internet Options / Advanced / Security):    . Check for publisher's certificate revocation    . Check for server ce…
In SQL Server, when rows are selected from a table, does it retrieve data in the order in which it is inserted?  Many believe this is the case. Let us try to examine for ourselves with an example. To get started, use the following script, wh…
Sending a Secure fax is easy with eFax Corporate (http://www.enterprise.efax.com). First, Just open a new email message.  In the To field, type your recipient's fax number @efaxsend.com. You can even send a secure international fax — just include t…
Polish reports in Access so they look terrific. Take yourself to another level. Equations, Back Color, Alternate Back Color. Write easy VBA Code. Tighten space to use less pages. Launch report from a menu, considering criteria only when it is filled…

760 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

22 Experts available now in Live!

Get 1:1 Help Now