Solved

asp.net set default button (enter) as user's control btnLogin

Posted on 2011-02-16
7
1,290 Views
Last Modified: 2012-08-13
trying to set login button (Button1) in user control as default button in the page default.aspx

 
LoginBox.ascx
------------- 
<asp:Button ID="Button1" runat="server" Text="Login" OnClick="Button1_Click" CssClass="mainbutton" />

Open in new window

0
Comment
Question by:doramail05
7 Comments
 
LVL 4

Expert Comment

by:ong-hh
ID: 34913147
0
 
LVL 13

Expert Comment

by:agarwalrahul
ID: 34913196
just put this property in your form tag (in aspx page):

defaultbutton="Button1"

 your form tag looks something like this:

<form id="form1" runat="server" defaultbutton="Button1">
0
 
LVL 11

Expert Comment

by:SAMIR BHOGAYTA
ID: 34913519
Hi, Use this javascript for set default button

function clickButton(e, buttonid)
{
var bt = document.getElementById(buttonid);
if (typeof bt == 'object'){
if(navigator.appName.indexOf("Netscape")>(-1)){
if (e.keyCode == 13){
bt.click();
return false;
}
}
if (navigator.appName.indexOf("Microsoft Internet Explorer")>(-1))
{
if (event.keyCode == 13){
bt.click();
return false;
}
}
}
}
0
Master Your Team's Linux and Cloud Stack

Come see why top tech companies like Mailchimp and Media Temple use Linux Academy to build their employee training programs.

 
LVL 20

Expert Comment

by:informaniac
ID: 34913538
Can u set the UseSubmitBehavior=true to the button in the usercontrol and check.
0
 
LVL 8

Expert Comment

by:Anurag Agarwal
ID: 34913547
hello doramail05!!


I think i got a better solution fr tht as default button technique won't help !!

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
       SetFocus("ClientIDGenerated_button_of_LoginBox.ascx")
    End Sub

to find client ID you just need to drag the LoginBox.ascx in aspx page and see the source code of the page. there u will find the client id (ID) generated for the login button which you want to set as default.
0
 
LVL 1

Accepted Solution

by:
doramail05 earned 0 total points
ID: 34913989
got it already,

Dim _uc As UserControl = DirectCast(Page.FindControl("loginBox1"), UserControl)

        Dim _btnClick As Button = DirectCast(_uc.FindControl("Button1"), Button)

        Form.DefaultButton = _btnClick.UniqueID

Open in new window

0
 
LVL 1

Author Closing Comment

by:doramail05
ID: 34941486
solved already from other post/forum
0

Featured Post

ScreenConnect 6.0 Free Trial

Want empowering updates? You're in the right place! Discover new features in ScreenConnect 6.0, based on partner feedback, to keep you business operating smoothly and optimally (the way it should be). Explore all of the extras and enhancements for yourself!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction Hi all and welcome to my first article on Experts Exchange. A while ago, someone asked me if i could do some tutorials on object oriented programming. I decided to do them on C#. Now you may ask me, why's that? Well, one of the re…
This article is for Object-Oriented Programming (OOP) beginners. An Interface contains declarations of events, indexers, methods and/or properties. Any class which implements the Interface should provide the concrete implementation for each Inter…
Although Jacob Bernoulli (1654-1705) has been credited as the creator of "Binomial Distribution Table", Gottfried Leibniz (1646-1716) did his dissertation on the subject in 1666; Leibniz you may recall is the co-inventor of "Calculus" and beat Isaac…
Finds all prime numbers in a range requested and places them in a public primes() array. I've demostrated a template size of 30 (2 * 3 * 5) but larger templates can be built such 210  (2 * 3 * 5 * 7) or 2310  (2 * 3 * 5 * 7 * 11). The larger templa…

773 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question