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Bourne Shell - if someone enters a variable that begins with...

Posted on 2011-02-17
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Last Modified: 2012-05-11
sorry, i know my questions are kind of basic, but i'm hoping you guys can help out

lets say if the user enters something that begins with "BL" but can be anything like BLsdf or BLUE or something..how can i figure this out?  I know it should be something along the lines of "BL"* or something but i'm not sure... if someone can point me in the right direction

i'm really trying to learn here

#!/bin/sh
echo -n "Enter a color: "
read color
if [ $color = bl* ]
then
 echo "blue"
fi

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Question by:nocturn4l
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4 Comments
 
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Accepted Solution

by:
ozo earned 500 total points
ID: 34914910
case $color in
 bl* ) echo "blue" ;;
esac
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Author Comment

by:nocturn4l
ID: 34914941
thanks again ozo, you're awesome.  is this something you can only do using case instead of 'if'?  still learning here, thanks again.
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LVL 84

Expert Comment

by:ozo
ID: 34915025
if expr "$color" : 'bl*' ; then echo blue ; fi
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Author Closing Comment

by:nocturn4l
ID: 34915085
thank you!  learning alot from everyone here
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