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how to move recordset into a vba array (similar to Excel code: varMyArray = myRange)

Posted on 2011-02-17
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Last Modified: 2012-06-22
In excel I often grab a range of cells and put them into a matrix for futher use.

In Access, I use a macro like the attached UDF.  
But, it occured to me that there might be an easier way and a better way to do it.

Does anybody have any comments?

Function RsToArray(rs As DAO.Recordset)
rs.MoveFirst
dim1ubound = rs.RecordCount
dim2ubound = rs.Fields.Count
Dim myArray()
ReDim myArray(0 To dim1ubound, 0 To dim2ubound - 1)
For i1 = 0 To dim1ubound
For i2 = 0 To dim2ubound - 1
myArray(i1, i2) = rs(i2)
Next
rs.MoveNext
Next
RsToArray = myArray
End Function

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Question by:rberke
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3 Comments
 
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Assisted Solution

by:VTKegan
VTKegan earned 80 total points
ID: 34916462
A recordset is an array essentially.  You access rows and columns using indexes directly on the recordset.  To me it doesn't make sense doing what you are doing.

I would just operate on the recordset instead of creating my own matrix of a recordset.
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Accepted Solution

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omgang earned 920 total points
ID: 34916498
I agree with VTKegan and prefer to work with the recordset directly.  But to your question the GetRows method may be worth looking into.  It will populate an array with records from a recordset.  It does the same thing as your function but will do so with a few less lines of code.
http://msdn.microsoft.com/en-us/library/bb221041(v=office.12).aspx

OM Gang
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Author Comment

by:rberke
ID: 34917274
Getrows looks like it will be exactly what I want (other than a superficial difference in that it is the transpose of what I wanted).  

And, I actually agree with comments about keeping the recordset intact 99% of the time.

But maybe 1% of the time using a matrix/array approach is useful.  

By analogy, an Excel Range is also essentially an array, yet about 5% of the time it is convenient for me to stick a range into a vba array.  In fact, I have found that quite a few Excel Gurus like to use the ary = Range approach for certain functions.

Thanks for your help.

rberke

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