Improve company productivity with a Business Account.Sign Up

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 737
  • Last Modified:

Split one column into two

Hi, I have a table that contains the following:

Term | Col | Department | Course | Course_Title

I need my Course Column split into two different columns Course and Course_Number. Examples for my course column include:

DAN 4640
FA  1040
MUED4120

So, some courses my have 1 space between the course and the number, while others have two spaces, or none. I'm not sure how to split these up so it will appear

Course | Course_Number
DAN        4640
FA           1040
MUED     4120

Any help would be greatly appreciated.
0
savache27
Asked:
savache27
  • 3
  • 2
  • 2
  • +2
1 Solution
 
pivarCommented:
Hi,

It seems you could use

select rtrim(left(Course, 4)) as Course, rtrim(right(Course, 4)) as Course_Number from yourtable

/peter
0
 
Luis PérezSoftware Architect in .NetCommented:
All course numbers are 4 digits length?
0
 
Kyle AbrahamsSenior .Net DeveloperCommented:
first format your string so that it only has one space.    Credit here: http://www.itjungle.com/fhg/fhg101106-story02.html for this part.  

then call fn_txt_split (code below)

SQL:

declare @test varchar(128)

set @test = 'this                test'

set @test =  replace(replace(replace(@test,' ','<>'),'><',''),'<>',' ')

select dbo.fn_txt_split(@test, " ")


/****** Object:  UserDefinedFunction [dbo].[fn_Txt_Split]    Script Date: 02/17/2011 10:18:45 ******/
IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[fn_Txt_Split]') AND type in (N'FN', N'IF', N'TF', N'FS', N'FT'))
DROP FUNCTION [dbo].[fn_Txt_Split]
GO

/****** Object:  UserDefinedFunction [dbo].[fn_Txt_Split]    Script Date: 02/17/2011 10:18:45 ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO


Create Function [dbo].[fn_Txt_Split]( 
    @sInputList varchar(8000) -- List of delimited items 
  , @Delimiter char(1) = ',' -- delimiter that separates items 
) 
RETURNS @list table (Item varchar(8000)) 
as begin 
DECLARE @Item Varchar(8000) 
  
  

WHILE CHARINDEX(@Delimiter,@sInputList,0) <> 0 
BEGIN 
SELECT 
@Item=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@Delimiter,@sInputList,0 
)-1))), 
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@Delimiter,@sInputList,0)+1,LEN(@sInputList)))) 
  
IF LEN(@Item) > 0 
INSERT INTO @List SELECT @Item 
  
END 

  
IF LEN(@sInputList) > 0 
INSERT INTO @List SELECT @sInputList -- Put the last item in 
  
return 
END 

GO

Open in new window

0
What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

 
Luis PérezSoftware Architect in .NetCommented:
If your course numbers are not always 4 digit length, you can try my snippet function.

Once the function created, you can do the following:
SELECT Course, dbo.getCourseNumber(Course) FROM myTable

Or to insert values into your new field:
UPDATE myTable SET Course_Number = dbo.getCourseNumber(Course)

Hope that helps.
CREATE FUNCTION getCourseNumber 
(
	@courseName varchar(100)
)
RETURNS INT
AS
BEGIN
	--First remove white spaces
	SET @courseName = REPLACE(@courseName, ' ', '')

	--Second split the numeric part
	WHILE ISNUMERIC(@courseName) = 0
		BEGIN
			SET @courseName = SUBSTRING(@courseName,2,LEN(@courseName)-1)
		END

	--Return the course number (casted as integer)
	RETURN CAST(@courseName AS INT)
END

Open in new window

0
 
Kyle AbrahamsSenior .Net DeveloperCommented:
sorry, the fn_txt_part was for multiple rows:

declare @test varchar(128)

set @test = 'this                test'

set @test =  replace(replace(replace(@test,' ','<>'),'><',''),'<>',' ')

select left(@test, charindex(' ', @test)-1) name, right(@test, len(@test)-charindex(' ', @test)) course

0
 
Kyle AbrahamsSenior .Net DeveloperCommented:
just realized you could also NOT have a space:

DECLARE @myString varchar(100);
DECLARE @course int;  
declare @name varchar(100)
SET @myString = 'DAN2456778'  
SET @course = reverse(LEFT( reverse(@mystring), PATINDEX('%[a-z]%',  reverse(@mystring)) - 1) )
set @name = replace(@mystring,@course,'')
select @name name, @course course
0
 
HainKurtSr. System AnalystCommented:
or this
with c as (
select 'DAN 4640' as course
union
select 'FA  1040'
union
select 'MUED4120'
)
select c.course,
REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(course,'0',''),'1',''),'2',''),'3',''),'4',''),'5',''),'6',''),'7',''),'8',''),'9','') cName,
ltrim(SUBSTRING(course, len(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(course,'0',''),'1',''),'2',''),'3',''),'4',''),'5',''),'6',''),'7',''),'8',''),'9',''))+1, LEN(course))) cNo
from c

course	cName	cNo
DAN 4640	DAN 	4640
FA  1040	FA  	1040
MUED4120	MUED	4120

Open in new window

0
 
HainKurtSr. System AnalystCommented:
or using a function

with c as (
select 'DAN 4640' as course
union
select 'FA  1040'
union
select 'MUED4120'
)
select c.course,
dbo.[RemoveNumeric](course) cName,
ltrim(SUBSTRING(course, len(dbo.[RemoveNumeric](course))+1, LEN(course))) cNo
from c

create function [dbo].[RemoveNumeric](
@s nvarchar(1000)  
) RETURNS nvarchar(1000)
begin
	return REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(@s,'0',''),'1',''),'2',''),'3',''),'4',''),'5',''),'6',''),'7',''),'8',''),'9','');
end;

Open in new window

0
 
savache27Author Commented:
Thank you, Pivar!! That worked perfectly!! I really appreciate the help.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

  • 3
  • 2
  • 2
  • +2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now