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Read folder content and search for specific filenames

Hi,


I have a php script to read a folder content:
<?php
if ($handle = opendir('attachments')) {
    while (($file = readdir($handle))!==false) {
		echo $file."<br/>";
    }
    closedir($handle);
}
?>

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and txt files inside:
OUT.101217.143529.Maersk-Test.txt
OUT.110107.151627.Maersk-Test.txt
OUT.110217.220100.Maersk-Test.txt
IN.101217.143529.Maersk-Test.txt
IN.110107.151627.Maersk-Test.txt

What I need is:
- Recognize the latest 'OUT' file (sort by filename, then pickup latest one would be the easiest way I suppose), from files above that would be "OUT.110217.220100.Maersk-Test.txt";
- check the first number in filename, "110217" in this case (number between 'OUT.' and '.') and check if there exist 'IN' file with the same number, if so, echo 'OK', if not, echo 'MISSING DATA';
 
Example step by step:
1. recognize latest file with name beginning with 'OUT': OUT.110217.220100.Maersk-Test.txt
2. take first number from filename: 110217
3. check if there exist file with filename beginning with 'IN.110217'
4. if exists, print 'OK', if not, print 'MISSING DATA';


Thanks for any help
0
Zado
Asked:
Zado
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1 Solution
 
Beverley PortlockCommented:
You might be better using scandir() which does the same job as opendir/readdir but returns the files as an array of filenames. That way you can use the standard sort() routine as well

$fileArray = scandir('attachments');
arsort( $fileArray );

arsort will sort in REVERSE order so the OUT files are done first and the latest number (the biggest?) will be the first one.  Once you have the filename it is a trivial task to swap its OUT for IN and access the array

$filename = $fileArray [0];
$inFile = str_replace("OUT.", "IN.", $filename );

if ( isset( $fileArray [ $inFile ] ) )
    echo "OK";
else
    echo "MISSING DATA";

0
 
Beverley PortlockCommented:
0
 
ZadoAuthor Commented:
Great idea, thanks, but there's something wrong in your script, no matter what happen, the script always prints 'MISSING DATA'
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Beverley PortlockCommented:
Silly me, the data is in the array as VALUES not as KEYS. I should have used in_array. Replace the IF in the code fragment with

if ( in_array( $inFile, $fileArray ) )

like so


$fileArray = scandir('attachments');
arsort( $fileArray );
$filename = $fileArray[0];

$inFile = str_replace("OUT.", "IN.", $filename );

if ( in_array( $inFile, $fileArray ) )
    echo "OK";
else
    echo "MISSING DATA";

Open in new window

0
 
ZadoAuthor Commented:
Thanks, almost done.
If filename is: OUT.110217.140029.Maersk-Test.ini
I'm interested if there exists IN.110217... in folder, I need to compare first number in filename only, not full filename, I've done some changes to your script, but don't know what to do next:

<?php
$fileArray = scandir('attachments');
arsort($fileArray);

$filename = $fileArray [0];
$subfilename = substr($filename, 4,6);

$inFile = str_replace("OUT.", "IN.", $filename );
$subinFile = substr($inFile, 3,6);

//I'm stuck here
if (in_array($subinFile,$fileArray)) { echo "OK"; }
else echo "MISSING DATA";
?>

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0
 
Beverley PortlockCommented:
We need a custom comparison system so replace the in_array in the IF with this function and also please replace arsort with rsort (see code below)

function maerskCompare( $filename, & $fileArray ) {
     $found = false;
     $inFile = preg_replace('!^[\.A-Z]+([0-9]+).*$!', 'IN.$1', $filename );

     foreach( $fileArray as & $aFile )
          if ( strpos( $aFile, $inFile ) !== false ) {
               $found = true;
               break;
          }

     return $found;
}

// ...... other code .......

rsort( $fileArray );
$filename = $fileArray[0];

$inFile = str_replace("OUT.", "IN.", $filename );


if ( maerskCompare( $inFile, $fileArray ) )
    echo "OK";
else
    echo "MISSING DATA";

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0
 
ZadoAuthor Commented:
Nice, thanks a lot for your help.
0

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