?
Solved

Using PostbackURL and AJAX

Posted on 2011-02-17
3
Medium Priority
?
640 Views
Last Modified: 2012-08-13
I have an ASP.Net/AJAX page named ViewLoads that is a fairly complex collection of updatepanels, multiviews, and controls of all kinds. It's working great.

Now I have added a control (cmdExportCampusTotals) which really has no code but has PostBackURL set to ~/GenerateFile.aspx. This activates that page in a hidden iFrame on the original page and downloads an Excel spreadsheet using this VB code:

    Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
        With Response
            .ClearContent()
            Dim filename As String
            filename = PreviousPage.SharedExportName
            .AddHeader("content-disposition", "attachment; filename=" & filename & ".xls")
            .ContentType = "application/ms-excel"
            .Write(PreviousPage.SharedOutput())
            .End()
        End With
    End Sub

Everything is working fine, and the original user interface still displays unscathed. But now, clicking any control in the page causes a postback to GenerateFile.aspx. How can I reset the page so that it posts back to ViewLoads.aspx instead?

Some of my searching has suggested using the RegisterStartupScript of the ScriptManager control, but I have not been successful in making that happen.
0
Comment
Question by:donrueter
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 9

Accepted Solution

by:
rawinnlnx9 earned 1000 total points
ID: 34921077
Enumerate each control and see if it has the PostbackURL property and if it does change that property.


I tried to do this from memory as I don't have VS where I am.
foreach (Control c in parent.Controls)
{
        PropertyInfo[] properties = c.GetType.GetProperties(); 

        foreach (PropertyInfo controlProperty in properties) 
        { 
            if (controlProperty.Name == "PostBackURL") 
            { 
            } 
        }
    
}

Open in new window

0
 
LVL 19

Expert Comment

by:Amandeep Singh Bhullar
ID: 35906850
This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.
0

Featured Post

The Orion Papers

Are you interested in becoming an AWS Certified Solutions Architect?

Discover a new interactive way of training for the exam.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

IntroductionWhile developing web applications, a single page might contain many regions and each region might contain many number of controls with the capability to perform  postback. Many times you might need to perform some action on an ASP.NET po…
For those of you who don't follow the news, or just happen to live under rocks, Microsoft Research released a beta SDK (http://www.microsoft.com/en-us/download/details.aspx?id=27876) for the Xbox 360 Kinect. If you don't know what a Kinect is (http:…
Do you want to know how to make a graph with Microsoft Access? First, create a query with the data for the chart. Then make a blank form and add a chart control. This video also shows how to change what data is displayed on the graph as well as form…
In this video you will find out how to export Office 365 mailboxes using the built in eDiscovery tool. Bear in mind that although this method might be useful in some cases, using PST files as Office 365 backup is troublesome in a long run (more on t…
Suggested Courses

741 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question