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Extract IMG from code

Posted on 2011-02-17
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Last Modified: 2012-05-11
Hi;
I have an array which in  $rss_channel["ITEMS"][$i]["DESCRIPTION"]   are my links to my images but images comes in this format

<p><a href="http://www.somesite.com/latourell_falls_columbia_river_oregon___1600x1-wallpapers.html" ><img src="http://www.somesite.com/thumbs/latourell_falls_columbia_river_oregon___1600x1-t2.jpg" align="left" /></a></p><br clear=all>

Whst would be the righ tsyntax with preg_match_all or anyother method I can get the link out in this format:

img src="http://www.somesite.com/thumbs/latourell_falls_columbia_river_oregon___1600x1-t2.jpg

Thanks a lot for the help
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Question by:babak62
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10 Comments
 
LVL 35

Expert Comment

by:Terry Woods
ID: 34921743
Generated from myregextester.com:

PHP Code Example:
<?php
$sourcestring="your source string";
preg_match_all('/img[^>]*src="[^"]*"/',$sourcestring,$matches);
echo "<pre>".print_r($matches,true);
?>
 
$matches Array:
(
    [0] => Array
        (
            [0] => img src="http://www.somesite.com/thumbs/latourell_falls_columbia_river_oregon___1600x1-t2.jpg"
        )

)
0
 

Author Comment

by:babak62
ID: 34922062
Thanks Terry for the response would you please tell me where should I incorporate this too
 $rss_channel["ITEMS"][$i]["DESCRIPTION"]  
0
 

Author Comment

by:babak62
ID: 34922080
Sorry for my ignorance I did it like this
$sourcestring= $rss_channel["ITEMS"][$i]["DESCRIPTION"];
preg_match_all('/img[^>]*src="[^"]*"/',$sourcestring,$matches);
echo "<pre>".print_r($matches,true);

and this is the output


Array
(
    [0] => Array
        (
            [0] => img src="http://www.w3wallpapers.com/thumbs/star_trails_mount_rainier_washington___1600x12-t2.jpg"
        )

)
 

0
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Author Comment

by:babak62
ID: 34922127
Treey;
Is ths supposed to print all the records or only one of the recoreds in the array
0
 
LVL 35

Expert Comment

by:Terry Woods
ID: 34922336
Did you want the array values updated, or just printed? Presumably $i is a variable number, in which case you'd do something like (pseudocode):

for each value of $i {
  $sourcestring= $rss_channel["ITEMS"][$i]["DESCRIPTION"];
  preg_match_all('/img[^>]*src="[^"]*"/',$sourcestring,$matches);
  print $matches[0];
}

or:
# Update the image tags:
for each value of $i {
  $rss_channel["ITEMS"][$i]["DESCRIPTION"] = preg_replace('/.*(img[^>]*src="[^"]*").*/',"$1", $rss_channel["ITEMS"][$i]["DESCRIPTION"]);
}
0
 

Author Comment

by:babak62
ID: 34922368
One more thing I need to ask you and that is my fault I need the tag without the  scr= and "" at the bgining and the end also
http://www.somesite.com/thumbs/latourell_falls_columbia_river_oregon___1600x1-t2.jpg
I did try the app you used but could not get this out would you PLEASR try this one more time and get me the results.  Whaat I need to do later is to use these URLs for either a slideshow or sonething like that and for that I only need the url to put it in the imgage tag later.
0
 
LVL 35

Expert Comment

by:Terry Woods
ID: 34922415
This should do it:

preg_match_all('/img[^>]*src="([^"]*)"/',$sourcestring,$matches);
print $matches[1];
0
 
LVL 35

Accepted Solution

by:
Terry Woods earned 2000 total points
ID: 34922481
This works for me:

$string = '<p><a href="http://www.somesite.com/latourell_falls_columbia_river_oregon___1600x1-w
allpapers.html" ><img src="http://www.somesite.com/thumbs/latourell_falls_columbia_river_oregon
___1600x1-t2.jpg" align="left" /></a></p><br clear=all>';

preg_match_all('/img[^>]*src\s*=\s*"([^"]*)"/i',$string,$matches);
print $matches[1][0];
0
 

Author Closing Comment

by:babak62
ID: 34922525
PERFECT ANSWER MILLION THANKS
0

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