vbs script to delete first file in a directory

What do you mean by first file?
First created file?
First name?
Random one of them?
Is this code the one you are looking for?

Dim fso, folder, files, sFolder, flf
  
  Set fso = CreateObject("Scripting.FileSystemObject")
  sFolder = "c:\tmp"
  Set folder = fso.GetFolder(sFolder)
  Set files = folder.Files
  
  For each flf In files
    flf.Delete
  Next

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Ops! You told only one file!
Here is tyhe corrected script

Dim fso, folder, files, sFolder, flf
  
  Set fso = CreateObject("Scripting.FileSystemObject")
  sFolder = "c:\tmp"
  Set folder = fso.GetFolder(sFolder)
  Set files = folder.Files
  
  For each flf In files
    flf.Delete
    exit for
  Next

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Well, what constitutes "first one"? In alphabetical order, by date, by size, by name length, by extension, ...?
Some examples for batch (.cmd) files (all in test mode, remove the ECHO to run them for real):

To delete the newest file in the current folder:

for /f "delims=" %%a in ('dir /a:-d /o:d /b') do set DeleteFile=%%a
ECHO del "%DeleteFile%"

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To delete the oldest file:

for /f "delims=" %%a in ('dir /a:-d /o:-d /b') do set DeleteFile=%%a
ECHO del "%DeleteFile%"

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To delete the alphabetically first file:
f

or /f "delims=" %%a in ('dir /a:-d /o:-n /b') do set DeleteFile=%%a
ECHO del "%DeleteFile%"

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And the alphabetically last file:

for /f "delims=" %%a in ('dir /a:-d /o:n /b') do set DeleteFile=%%a
ECHO del "%DeleteFile%"

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I don't want to delete them all. I just want to delete the first one in the list. The date is not important, the size is not important. I just want to delete the first one.

With my second post you can delete only a file.
But again. First by name or what?

That looks better. How do I delete the newest one? With VBS please

Thanks a lot. This solved my problem