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Xsl Nested Loop

I am trying to display a subset of data that matches based on the ExchangeWantedId. How do I set this up? Here is what I have thus far:

Here is the XML

<xs:element name="ExchangeWantedItemsMeToodUsers">
<xs:complexType>
- <xs:sequence>
<xs:element name="ExchangeWantedId" type="xs:int" minOccurs="0" />
<xs:element name="ExchangeWantedName" type="xs:string" minOccurs="0" />
<xs:element name="MeTooer" type="xs:string" minOccurs="0" />
<xs:element name="MeTooerBankName" type="xs:string" minOccurs="0" />
<xs:element name="DateFulfilled" type="xs:string" minOccurs="0" />
<xs:element name="DateFulfilledUnformated" type="xs:dateTime" minOccurs="0" />
<xs:element name="UserID" type="xs:int" minOccurs="0" />
<xs:element name="FullName" type="xs:string" minOccurs="0" />
<xs:element name="PostedBankName" type="xs:string" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
- <xs:element name="ExchangeWantedItemsMeToodUsers1">
- <xs:complexType>
- <xs:sequence>
<xs:element name="ExchangeWantedID" type="xs:int" minOccurs="0" />
<xs:element name="DisplayName" type="xs:string" minOccurs="0" />
<xs:element name="FullName" type="xs:string" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
Here is the xsl

<xsl:for-each select="/root/ExchangeWantedItemsMeToodUsers">
<tr>
<xsl:call-template name="AlternateRowColor" />
<td><xsl:value-of select="ExchangeWantedName" /></td>
<td>
<xsl:for-each select="/root/ExchangeWantedItemsMeToodUsers">
<xsl:value-of select="MeTooer" /> - <xsl:value-of
select="MeTooerBankName" />
</xsl:for-each>
</td>
<td><xsl:value-of select="FullName" /> - <xsl:value-of
select="PostedBankName" /></td>
<td><xsl:value-of select="DateFulfilled" /></td>
</tr>
</xsl:for-each>

ASKER CERTIFIED SOLUTION

Gertone (Geert Bormans)

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Gertone (Geert Bormans)

https:#a34931805 contains an general good advice above selectivity in apply templates / for-each AND it contains an important suggestion about inner context of a for-each loop, something a lot of XSLT beginners struggle with

Please accept that comment as an answer