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jQuery .POST not posting results on html

I don't see what I am doing wrong.

Here is the code
$("#EntireMenu a").live('click',function(){
					
				//$('.divPage:last').remove();
					var myObj = $(this);
				
				switch ($(this).attr('class')){
					case 'mReports':
						$('.divPage:first').fadeOut(50, function(){
								$(this).remove();
						});
						$("<div/>", {
				      "id": "RepPage",
				      "class":"divPage1",
															}).hide().appendTo("#body"); 
						$.ajax({
										type:"POST",
										url:'/aaMain/reports.php',
										data:{repType: myObj.attr('href').split('#')[1]
											},
										dataType:'json',
										success:function(responseText){
												// handle response
												alert('we got somethn!');
												$('#RepPage').html(responseText, function(){
														$('#RepPage').show();
													});
											}
									});
						
						//alert ('we got class - mReports!');
						var width_div = $('.divPage table').width() ? $('.divPage table').width() :1200;
						
		    		$('#footer').css({'position':'absolute','top':'500', 'width':width_div});
		      	$('#footer').fadeIn();
		      	// get data
		      	
						return false;
						break;

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the switch continues.... but the code that is not working is what is above.

In firebug I can see more of what is going on , but I still don't understand why it shows the html in firebug but not on my page see attached image.
jQuery-POST.png
0
gbeaulac
Asked:
gbeaulac
  • 6
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1 Solution
 
leakim971PluritechnicianCommented:
Try an synchrone ajax call, so replace your current ajax call by the following :


var rt = $.ajax({type:"POST",url:'/aaMain/reports.php',data:{repType: myObj.attr('href').split('#')[1]},dataType:'json',"async":false}).responseText;
					alert('we got somethn!');
					$('#RepPage').html(rt, function() { $('#RepPage').show(); });

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gbeaulacAuthor Commented:
It spits out the alert, but still does not show the html.
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leakim971PluritechnicianCommented:
do you get your html code in the alert with the following ?
var rt = $.ajax({type:"POST",url:'/aaMain/reports.php',data:{repType: myObj.attr('href').split('#')[1]},dataType:'json',"async":false}).responseText;
alert(rt);
$('#RepPage').html(rt);
$('#RepPage').show();

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gbeaulacAuthor Commented:
YES!

I removed the alert and now we have display!

But can you also tell me what was wrong with my code? Why it would not work?
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gbeaulacAuthor Commented:
This is the second time you have helped me. I am grateful.
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gbeaulacAuthor Commented:
When I make a second choice from my menu, it does not display until I reclick the menu. Any reason for that?
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gbeaulacAuthor Commented:

I was reading your code and just clued in (even though you mentioned it in your first answer) that we are not going async. Isn't that defeating the purpose of using ajax?
I am sure you have a good reason, don't get me wrong, but I was wondering if you could explain why that is, please?

Sorry about the tons of questions...
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leakim971PluritechnicianCommented:
>When I make a second choice from my menu, it does not display until I reclick the menu. Any reason for that?
>I was reading your code and just clued in (even though you mentioned it in your first answer) that we are not going async. Isn't that defeating the purpose of using ajax?

I was thinking we need to wait the data before continue the switch
With an async ajax call the program don't wait the end of the call and continue. So if you're doing thing thinking the data is available, it's not the case, for example moving a div of changing style attibute of object not available (before the end of the ajax call)

generaly you can use a async ajax call (generaly) but you need to have control of all what happen in the code.
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gbeaulacAuthor Commented:
ok Thank you
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leakim971PluritechnicianCommented:
np, have a nice sunday !
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