Getting portion of php string

Hi,

Something around this line :

$str = substr($str, 0, strlen(strpos($str,"mp3") + 3))

Or - if this is always an address at the beginning,

$str = "http://www.site.com/blog/2011/02/01/filetoaudio-baker.mp3 6787576 audio/mpeg";
$strarr = explode(" ",$str);
$myfile = trim($strarr[0]);

the parseurl function of php should do it:
http://www.php.net/manual/en/function.parse-url.php

To get just the file name, explode the string at spaces, if you want the file without the path use basename to get only the file portion - this example gives you both:

$str="http://www.site.com/blog/2011/02/01/filetoaudio-baker.mp3 6787576 audio/mpeg";
@list($file,$extra_data)=explode(" ",$str);
echo $file; // print complete url
echo "\n";
echo basename($file); // print file name from url only

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-output will be:
http://www.site.com/blog/2011/02/01/filetoaudio-baker.mp3
filetoaudio-baker.mp3

@angelIII: Using that function I get the non desired strins in the path returned:

Array ( [scheme] => http [host] => www.blogtalkradio.com [path] => /newcaptainsofind ustry/2011/02/01/america-west-resources-ceo-dan-baker.mp3 6787576 audio/mpeg ) 

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@Roads_Roads your solution wont work if file name contains a whitespace.

How about BurineP's solution ?

@MatthewP: your solution wont work if file name contains a whitespace.

Burine's solution does not works. It returns just 2 letters: ht

That is assuming one space only as a separator between the various parts. If there may be more swap line 2 for:

$split_at_space=preg_split("/\s+/",$str);

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<?php
    $str = "http://www.site.com/blog/2011/02/01/file toaudio-baker.mp3 6787576 audio/mpeg";
    $mystr = trim(substr($str, 0, strpos($str,"mp3")+3));
    echo"$mystr";
?>

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http://www.laprbass.com/RAY_temp_fernanditos.php

Outputs:
array(3) {
  [0]=>
  string(57) "http://www.site.com/blog/2011/02/01/filetoaudio-baker.mp3"
  [1]=>
  string(7) "6787576"
  [2]=>
  string(10) "audio/mpeg"
}

<?php // RAY_temp_fernanditos.php
error_reporting(E_ALL);
echo "<pre>";

// TEST DATA FROM THE POST AT EE
$str = "http://www.site.com/blog/2011/02/01/filetoaudio-baker.mp3 6787576 audio/mpeg";

// USE EXPLODE TO ISOLATE THE PARTS OF THE STRING
$arr = explode(' ', $str);

// SHOW THE ISOLATED PARTS
var_dump($arr);

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Oh, that said, using that method if you may have multiple spaces together as separators there will be more work if the file name may also contain multiple spaces as part of the name.

Another way, actually with much less code:

$str="http://www.site.com/blog/2011/02/01/file  toaudio-baker.mp3  6787576    audio/mpeg";
$result=preg_match("/.*\.\w+/",$str,$matches);
echo $matches[0];

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@Roads, sorry I did not see your last solution. Matthew's solution is working great.

However if I give a dynamic value to $str instead of static ".." then $file returns empty.

I have opened another question for that related issue. Can you help there?

https://www.experts-exchange.com/questions/26834559/Passing-simple-php-value-in-Wordpress-single-php-file.html

Thank you all!