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purplesoupFlag for United Kingdom of Great Britain and Northern Ireland

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Why can z^3 = -27 be written as r^3(cos(3(theta)+i.sin(3(theta))?

I'm working with complex numbers and reading through a solution,

It begins like this - In polar form, -27 = 27 (cos(pi) + i sin(pi))

I get that, but then it says

If z = r(cos(theta)+i sin(theta), then the equation z^3 = -27 can be written as

r^3(cos(3(theta)+i.sin(3(theta)) = 27(cos(pi) + i sin(pi))

I don't see where the left hand side came from??


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phoffric

It comes from Euler's formula - http://en.wikipedia.org/wiki/Euler's_formula

e^(i theta) == cos(theta) + i sin(theta)

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phoffric

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That's great - thanks!