sort excel output into unique rows

Hi

Sid on this site kindly posted the following code to sort excel data based on the content of rows from another tab in excel.  I would like to do is for it to then sort the output into unique rows so that I can show only the unique records of one of the output columns.  the code is as follows.

Sub Sample()
    Dim ws1 As Worksheet
    Dim ws1LastRow As Long
   
    Set ws1 = Sheets("Sheet1")
   
    With ws1
    ws1LastRow = .Range("A" & Rows.Count).End(xlUp).Row
   
        .Columns("B:B").Insert Shift:=xlToRight, CopyOrigin:=xlFormatFromLeftOrAbove
        .Range("B2").FormulaR1C1 = "=VLOOKUP(RC[-1],Sheet2!C[-1],1,0)"
        .Range("B2").AutoFill Destination:=Range("B2:B" & ws1LastRow)
        .Range("B2:B8").Copy
        .Range("B2:B8").PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, _
        SkipBlanks:=False, Transpose:=False
        .Range("B1").FormulaR1C1 = "Temp"
        .Range("A1:C8").Select
   
        Application.CutCopyMode = False

        .Columns("A:C").Sort Key1:=Range("B2"), Order1:=xlAscending, Header:=xlYes, _
        OrderCustom:=1, MatchCase:=False, Orientation:=xlTopToBottom, DataOption1:=xlSortNormal
        .Range("A1:C1").AutoFilter
        .Range("$A$1:$C$" & ws1LastRow).AutoFilter Field:=2, Criteria1:="#N/A"
        .Range("$A$1:$C$" & ws1LastRow).Offset(1, 0).SpecialCells(xlCellTypeVisible).EntireRow.Delete
        .Columns("B:B").Delete Shift:=xlToLeft
        .Range("A1:C1").AutoFilter
    End With
End Sub
stefanjocAsked:
Who is Participating?
 
SiddharthRoutConnect With a Mentor Commented:
Try this. Sample File Attached.

Sub Sample()
    Dim ws1 As Worksheet
    Dim ws1LastRow As Long, x As Long
    
    Set ws1 = Sheets("Sheet1")
    
    With ws1
    ws1LastRow = .Range("A" & Rows.Count).End(xlUp).Row
    
        .Columns("B:B").Insert Shift:=xlToRight, CopyOrigin:=xlFormatFromLeftOrAbove
        .Range("B2").FormulaR1C1 = "=VLOOKUP(RC[-1],Sheet2!C[-1],1,0)"
        .Range("B2").AutoFill Destination:=Range("B2:B" & ws1LastRow)
        .Range("B2:B8").Copy
        .Range("B2:B8").PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, _
        SkipBlanks:=False, Transpose:=False
        .Range("B1").FormulaR1C1 = "Temp"
        .Range("A1:C8").Select
    
        Application.CutCopyMode = False

        .Columns("A:C").Sort Key1:=Range("B2"), Order1:=xlAscending, Header:=xlYes, _
        OrderCustom:=1, MatchCase:=False, Orientation:=xlTopToBottom, DataOption1:=xlSortNormal
        .Range("A1:C1").AutoFilter
        .Range("$A$1:$C$" & ws1LastRow).AutoFilter Field:=2, Criteria1:="#N/A"
        .Range("$A$1:$C$" & ws1LastRow).Offset(1, 0).SpecialCells(xlCellTypeVisible).EntireRow.Delete
        .Columns("B:B").Delete Shift:=xlToLeft
        .Range("A1:C1").AutoFilter
        
        ws1LastRow = .Range("A" & Rows.Count).End(xlUp).Row
    
        For x = ws1LastRow To 1 Step -1
            If Application.WorksheetFunction.CountIf(.Range("A1:A" & x), .Range("A" & x).Text) > 1 Then
                .Range("A" & x).EntireRow.Delete
            End If
        Next x
    End With
End Sub

Open in new window

Sort-Example.xls
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stefanjocAuthor Commented:
Hi ya.  Sorry haveny got back to you, rushed afternoon.  I have had a look at the bit that removes the duplicates and its removing everything but one.  What I meant was to sort the colum so that it only shows one entry for each person.  so, andy and frank may have access to more than one mailbox, however after the sort I dont want two franks in the list, just one?  Do you see what I mean?

mailbox9      andy
mailbox9      frank
mailbox9      bob
mailbox6      andy
mailbox6      bob
mailbox6      andy
mailbox6      Frank
mailbox6      Frank
mailbox1      bob
mailbox1      andy
mailbox5      Sid
mailbox5      frank
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SiddharthRoutCommented:
I just tested it. It is working just fine :)

Please upload your excel file with a sample data so that I can test it.

Sid
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TracyVBA DeveloperCommented:
This question has been classified as abandoned and is being closed as part of the Cleanup Program. See my comment at the end of the question for more details.
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