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Use of HAVING and WHERE conditon of something with count > 1

Hi,
I have a tbl named Order_Discount that stores all order line items that get a discount per order.
I need to write a SQL statement that lists the OrderIDs of all orders that have one or more line items discounted.

I've started the SQL but I don't think it's correct:

SELECT OrderID, OrderLineItemID, DiscountYN
FROM Order_Discount
WHERE DiscountYN = 'Y'
HAVING COUNT(DiscountYN ) > 1

I need to see all OrderID's along with their OrderLineItemID's where one or more OrderLineItemID has a 'Y' for DiscountYN. I don't want to include only those orders that have ALL discounted order line items, having line item id(s) with no discount is ok too (DiscountYN = 'N') as long as one or more order line items per order have a discount. Can I do something like this: HAVING COUNT(DiscountYN ) > 1 WHERE DiscountYN = 'Y'. I know this is bad syntax - what would be the correct syntax to use in my case?

Best regards,
WDelaney
 
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wdelaney05
Asked:
wdelaney05
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1 Solution
 
Alex MatzingerDatabase AdministratorCommented:
Try this:
SELECT OrderID, OrderLineItemID, DiscountYN
FROM Order_Discount
WHERE OrderID IN ( SELECT Distinct OrderID
                                       FROM Order_Discount
                                       WHERE DiscountYN = 'Y')

If an OrderID has any discounted item in it, this will return the entire order id with all orderlineitmeids as well

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wolfgang_93Commented:
Try something like this (I did not test this so may need tweaking):

SELECT OrderID, OrderLineItemID, DiscountYN
FROM Order_Discount
WHERE OrderID in (
  SELECT OrderID FROM Order_Discount
  WHERE DiscountYN='Y'
  GROUP by DiscountYN
  HAVING COUNT(DiscountYN)>0
  )


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wolfgang_93Commented:
Oops. I see amatzinger got their response in before mine and it looks like it will
do the job better as it does not involve GROUP BY and HAVING COUNT
as mine does.
0
 
Alex MatzingerDatabase AdministratorCommented:
also, inorder to use the having count() clause, you would need a group by clause.

But i don't believe you can do this with just one query, i believe that the nested query is the way to go on this one.
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