Solved

evenly distribute items

Posted on 2011-02-21
12
417 Views
Last Modified: 2012-05-11
if $x<=4 do one row
if $x<=8 && $x>=5 two rows
if $x>=9 three rows


I need to do

<table>
<tr>
<td>

and I want the items to evenly distributed


so if $x==5
3 items on first row
2 items on second row
0
Comment
Question by:rgb192
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12 Comments
 
LVL 27

Expert Comment

by:Lukasz Chmielewski
ID: 34946312
By an item you mean ... ? What is $x ?
With what I understood, you need to distribute let's say numbers from 1to $x. So if the $x is:
1,2,3,4 - <td>1234</td>
5 <tr><td>123</td></tr><tr><td>45</td></tr>
6 <tr><td>123</td></tr><tr><td>456</td></tr>
7 <tr><td>1234</td></tr><tr><td>567</td></tr>
8 <tr><td>1234</td></tr><tr><td>5678</td></tr>
9<tr><td>123</td></tr><tr><td>456</td></tr><tr><td>789</td></tr>

right ?
0
 

Author Comment

by:rgb192
ID: 34946438
yes

how to do this in php
0
 

Author Comment

by:rgb192
ID: 34946450
$x is count of items


each item has an image
echo'<img src='.$x.'>';
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LVL 27

Expert Comment

by:Lukasz Chmielewski
ID: 34946566
So the $x variable is an array ? If yes, let's get the count of items in it.

<table>
<?php
// count the items in an array 
$num = count($x);
   switch($x){
      case 1,2,3,4: 
         echo"<tr><td>";
         for($i=0$i<$num;$i++)
            echo"<img src='$x[$i]' />";
         echo"</td></tr>"; break;

      case 5: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /></td></tr>"; 
         echo"<tr><td><img src='$x[3]' /><img src='$x[4]' /></td></tr>"; 
         break;

      case 6: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /></td></tr>"; 
         echo"<tr><td><img src='$x[3]' /><img src='$x[4]' /><img src='$x[5]' /></td></tr>"; 
         break;

      case 7: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /><img src='$x[3]' /></td></tr>"; 
         echo"<tr><td><img src='$x[4]' /><img src='$x[5]' /><img src='$x[6]' /></td></tr>"; 
         break;

      case 8: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /><img src='$x[3]' /></td></tr>"; 
         echo"<tr><td><img src='$x[4]' /><img src='$x[5]' /><img src='$x[6]' /><img src='$x[7]' /></td></tr>"; 
         break;
   }

   // TO DO
   // handling of more than 9 items
   
?>
</table>

Open in new window


The more than 9 items situation - what if there are 14 items - it means that there should be 3 rows with 5,5,4 items ?
0
 
LVL 110

Expert Comment

by:Ray Paseur
ID: 34946678
I may not be getting the concept exactly right, but try this and see if it makes sense to you.  On the web at:
http://www.laprbass.com/RAY_temp_rgb192.php
<?php // RAY_temp_rgb192.php
error_reporting(E_ALL);
echo "<pre>";


// FROM THE POST AT EE:
// evenly distribute items
// Question:
// if $x<=4 do one row
// if $x<=8 && $x>=5 two rows
// if $x>=9 three rows


// IF ANYTHING POSTED
if (!empty($_POST["i"]))
{
    // GET THE POSTED DATA IN A LOCAL VAR
    $i = (int)trim($_POST["i"]);

    // MAYBE MAKE SOME SANITY CHECKS ABOUT THE NUMBER HERE

    // START THE TABLE
    echo "VIEW SOURCE TO SEE THE TABLE" . PHP_EOL;
    echo "<table>" . PHP_EOL;

    while ($i)
    {
        // SET THE COUNTER FOR THE ROW
        $n = 4;

        // START THE ROW
        echo "<tr>" . PHP_EOL;

        while ($n)
        {
            // START THE DATA ELEMENTS
            echo "<td>$i</td>" . PHP_EOL;

            // DECREMENT THE COUNTER
            $i--;

            // FILLS OUT THE ROW WITH EMPTY CELLS
            if ($i == 0) $i = NULL;

            // COUNT CELLS PER ROW
            $n--;
        }

        // END OF THIS ROW
        echo "</tr>" . PHP_EOL;
    }

    // END OF THIS TABLE
    echo "</table>" . PHP_EOL;
}

// END PHP, PUT UP THE FORM
?>
<form method="post">
ENTER A NUMBER BETWEEN 1 AND 9
<input name="i" />
<input type="submit" />
</form>

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0
 

Author Comment

by:rgb192
ID: 34948842
ray answer was not 'even'
there was a
4 in one row
and
2 in another row

wanted 3 3


>>The more than 9 items situation - what if there are 14 items - it means that there should be 3 rows with 5,5,4 items ?

and roads answer
was correct
but  how do to 3 rows

5
5
4
is what I want

0
 
LVL 27

Accepted Solution

by:
Lukasz Chmielewski earned 400 total points
ID: 34949284
Try this:

<table border="1">
<?php

$x = array('1','2','3','4','5','6','7','8','9','10','11','12','13','14');

// count the items in an array 
$num = count($x);
   switch($num){
      case 1: 
         echo"<tr><td>";
         for($i=0;$i<$num;$i++)
            echo"<img src='$x[$i]' />";
         echo"</td></tr>"; break;
      case 2:          
         echo"<tr><td>";
         for($i=0;$i<$num;$i++)
            echo"<img src='$x[$i]' />";
         echo"</td></tr>"; break;
      case 3: 
         echo"<tr><td>";
         for($i=0;$i<$num;$i++)
            echo"<img src='$x[$i]' />";
         echo"</td></tr>"; break;
      case 4: 
         echo"<tr><td>";
         for($i=0;$i<$num;$i++)
            echo"<img src='$x[$i]' />";
         echo"</td></tr>"; break;                  
      case 5: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /></td></tr>"; 
         echo"<tr><td><img src='$x[3]' /><img src='$x[4]' /></td></tr>"; 
         break;

      case 6: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /></td></tr>"; 
         echo"<tr><td><img src='$x[3]' /><img src='$x[4]' /><img src='$x[5]' /></td></tr>"; 
         break;

      case 7: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /><img src='$x[3]' /></td></tr>"; 
         echo"<tr><td><img src='$x[4]' /><img src='$x[5]' /><img src='$x[6]' /></td></tr>"; 
         break;

      case 8: 
         echo"<tr><td><img src='$x[0]' /><img src='$x[1]' /><img src='$x[2]' /><img src='$x[3]' /></td></tr>"; 
         echo"<tr><td><img src='$x[4]' /><img src='$x[5]' /><img src='$x[6]' /><img src='$x[7]' /></td></tr>"; 
         break;
   }

   // TO DO
   // handling of more than 9 items
   if($num >= 9){
   $numrows = 3;
   
   // how much items do we have left
   $itemsleft = $num;
   $firstitem = 0;
   
   for($i=$numrows;$i>0;$i--){
    echo"<tr><td>";
    
    // first row items
    $numitems = ceil($itemsleft/$i);
    // substract the items
    $itemsleft = $itemsleft - $numitems;
    
    for($j=$firstitem;$j<$firstitem+$numitems;$j++)
    echo"<img src=".$x[$j]." />";
    $firstitem = $firstitem + $numitems;
    
    echo"</td></tr>";
   }
   
   }
   
?>
</table>

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0
 
LVL 110

Assisted Solution

by:Ray Paseur
Ray Paseur earned 100 total points
ID: 34950804
@Roads_Roads:  To save you some typing, see http://us2.php.net/manual/en/function.range.php

$x = array('1','2','3','4','5','6','7','8','9','10','11','12','13','14'); can be written $x = range(1,14);

@rgb192: If what you really want is the distribution of 14 items, please tell us that when you post the question.  The question showed 9 items, not 14.  And it is still not clear how you want these distributed.  Which is more important to you - the number of rows or the number of items per row?
0
 
LVL 27

Expert Comment

by:Lukasz Chmielewski
ID: 34950840
Thanks Ray I was not aware of that function.

I assume that the range is closed downwards (of course...) with only one item - the specific case is that when the number of items is >= 9, so what I did was to add some more to that, to see if the function works.
0
 

Author Comment

by:rgb192
ID: 34952440
>>Which is more important to you - the number of rows or the number of items per row?

 the number of items per row
0
 

Author Closing Comment

by:rgb192
ID: 34953118
0
 

Author Comment

by:rgb192
ID: 34953133
0

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