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Generate table owner list for all the tables in a database

Posted on 2011-02-21
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Last Modified: 2013-11-24
I am using SQL 2008 please how do I write a query to generate table owner list and sizes for all the tables in a database. The query headings will be TABLENAME, OWNER, SIZE
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Question by:agbelo
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10 Comments
 
LVL 15

Expert Comment

by:jorge_toriz
ID: 34948274
Well, I think this can help you as a start point:

SELECT SCHEMA_NAME(T.[schema_id]) + '.' + T.name, USER_NAME(S.principal_id) AS Owner
FROM sys.tables T
INNER JOIN sys.schemas S
ON T.[schema_id] = S.[schema_id]
ORDER BY T.name

In SQL Server 2008 the owner is the one that own the schema where the object resides.
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LVL 15

Accepted Solution

by:
jorge_toriz earned 500 total points
ID: 34948282
Well, in the preceeding sentence, I must fix: "the owner (in tables) is the one that own the schema where the object resides"
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Author Comment

by:agbelo
ID: 34952700
That was surely very helpful so what about if this was for a SQL 2000 server? How would the code look?
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Author Closing Comment

by:agbelo
ID: 34952757
Solution will be complete when my follow up question is answered
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Author Comment

by:agbelo
ID: 34952789
And also include the table sizes column in your answer
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LVL 15

Expert Comment

by:jorge_toriz
ID: 34952794
Ups... I can't really remember anything about sql 2000, let me find the system views and verify if this information can be get
0
 
LVL 15

Expert Comment

by:jorge_toriz
ID: 34952892
Well, you can get the estimated row size with this one:

SELECT SCHEMA_NAME(T.[schema_id]) + '.' + T.name, USER_NAME(S.principal_id) AS Owner, SUM(C.max_length) AS EstimatedRowSize
FROM sys.tables T
INNER JOIN sys.schemas S
ON T.[schema_id] = S.[schema_id]
INNER JOIN sys.columns C
ON T.[object_id] = C.[object_id]
GROUP BY T.[schema_id], T.name, S.principal_id
ORDER BY T.name
0
 

Author Comment

by:agbelo
ID: 34953077
Please I asked for the estimated table size for each table and make values return in MB
0
 

Author Comment

by:agbelo
ID: 34953155
I actuallly have a query that would do what I need I just need to re-engineer it to give me the object owners. Maybe you can help me here. Below is the query I am using and it works in both SQL 2000 and SQL 2008. Please help to modify it to return the object owners

SELECT so.[name], used AS "# of Pages", rows AS "# of Rows", (used * 8) /
1024 AS "# of MB"  
FROM sysobjects so JOIN sysindexes si ON so.id = si.id
WHERE so.xtype = 'U'
ORDER BY used DESC
0
 
LVL 15

Expert Comment

by:jorge_toriz
ID: 34953375
You can use this query to get the table size:

SELECT T.name AS TableName, SUM(P.record_count * P.avg_record_size_in_bytes) AS TotalSize
FROM sys.tables T
CROSS APPLY sys.dm_db_index_physical_stats(DB_ID(), NULL, NULL, NULL, 'DETAILED') AS P
WHERE T.[object_id] = P.[object_id]
GROUP BY T.name
ORDER BY T.name
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