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How to use "and" in a when statement

Posted on 2011-02-22
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Last Modified: 2013-11-08
I have a template that receives 2 parameters. This template runs a key function to compare a value .
I want the condition to read when key is found AND 2nd parameter value equals the string "x2" then return the value found in the key.

right now i have the following:
but i want to include the and-statement, but I keep getting error that missing variable is not declared.

please advise on syntax

   
<xsl:template name="getVal">
    <xsl:param name="code"/>
    <xsl:param name="missing"/>
   
    <xsl:choose>

      <xsl:when test="key('oldData', $code)" > <!--and $missing ='x2'>-->

        <xsl:value-of select="key('oldData', $code)/x2"/>
      </xsl:when>

    </xsl:choose>
  </xsl:template>

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Question by:badtz7229
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Accepted Solution

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Geert Bormans earned 2000 total points
ID: 34953256
<xsl:when test="key('oldData', $code) and $missing ='x2' ">
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Expert Comment

by:Geert Bormans
ID: 34953316
could be that you are not passing anything to $missing?
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Author Comment

by:badtz7229
ID: 34953975
i see i was missing the double quotes in my and-statement.
Gertone: you are right. my $missing is null.
i am passing a string into this variable during my function call.
see below

so i'm not sure if my syntax for passing a variable is incorrect. i tried with single and double quotes but i still get null
<xsl:call-template name="getVal">
                <xsl:with-param name="code" select="$pk"/>
                <xsl:with-param name="missing" select='x2'/>
              </xsl:call-template>

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Author Comment

by:badtz7229
ID: 34954080
nevermind, i got it. i was missing doubel quotes outside
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Expert Comment

by:Geert Bormans
ID: 34954116
passing the parameter is right
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Expert Comment

by:Geert Bormans
ID: 34954119
OK, I see
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Author Comment

by:badtz7229
ID: 34954120
i'm wondering though - since my "missing" parameter is actually an element name can i do something like  below?
where i pass missing variable into my value=of select?
 i keep getting error when i do this, perhaps my syntax is off
<xsl:choose>
      <xsl:when test="key('oldData', $code)" > 
        <xsl:value-of select="key('oldData', $code)/$missing"/>
      </xsl:when>
    </xsl:choose>

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Expert Comment

by:Geert Bormans
ID: 35219071
no you can't

  <xsl:value-of select="key('oldData', $code)/$missing"/>

should be

  <xsl:value-of select="key('oldData', $code)/*[name() = $missing]"/>
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