Convert HexaDecimal Strng to Byte Array Using Java

Hello,

I'm trying to find out how to convert a hexadecimal string to a byte array using Java.

For example if I want to display a value such as d079061eff52d88e8ef80db06461466e as "-38, 111, 6, 31, 91, 81, -40, -114, -114, -40, 13, -80, 116, 97, 72, 110" then what do I do. (The above is a made up hex string just for representation here)

I've tried to do this using a class as per the code snippet I've attached here But it prints out something similar to "Ðy\RØŽŽØ
°taHn"

That is not what I want though as I want the numbered format similar to the numbers 38, 111, 6, 31,  etc above.


Any ideas/help on this?

Thanks!

public class CipherTextByteConverter {
	
	public CipherTextByteConverter(){
		
	}
	
    public static void main(String[] args) {

    	CipherTextByteConverter cipherConvert=new CipherTextByteConverter();
    	
        String hexVal = "d079061eff52d88e8ef80db06461466e";
       String value = new String(cipherConvert.hexToBytes(hexVal));
        
        System.out.println(value);

    }	

    public static byte[] hexToBytes(String hexVal) {
        int len = hexVal.length();
        byte[] data = new byte[len / 2];
        for (int i = 0; i < len; i += 2) {
          data[i / 2] = (byte) ((Character.digit(hexVal.charAt(i), 16) << 4)
      	                             + Character.digit(hexVal.charAt(i+1), 16));
        }
        
        return data;
    }	    
}

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