Remove all charaters after 2 decimal places

I need to remove all numbers after 2 decimal places rounding accordingly in a specific column in vba

It would turn 27.545 to 27. 55

I need what's typed in the cell to actually look like 27.55 also since I am importing this spreadsheet after and it won't take if it's 27.545
techpr0Asked:
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jppintoCommented:
Something like this should do it:

ActiveSheet.Cells(2, 2).Value = Round(ActiveSheet.Cells(2, 2).Value, 2)
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jppintoCommented:
For the entire column, you can use something like this.

jppinto
Dim wb As Workbook, ws As Worksheet
Dim cell As Range
 
Set wb = ActiveWorkbook
Set ws = ActiveSheet
 
For Each cell In ws.Range("B:B")
    cell.Value=Round(cell.Value,2)
Next cell

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techpr0Author Commented:
jppinto,
   Your second solution worked, but how do i get it to skip row 1 ( the header row)?
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jppintoCommented:
Use this code instead...

jppinto
Sub teste()
Dim wb As Workbook, ws As Worksheet
Dim cell As Range
Dim lstrow As Long
lstrow = Cells(65536, "B").End(xlUp).Row
 
Set wb = ActiveWorkbook
Set ws = ActiveSheet
 
For Each cell In ws.Range("B1:B" & lstrow)
   cell.Value=Round(cell.Value,2)
Next cell

End Sub

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jppintoCommented:
Sorry...typo! Change this line:

For Each cell In ws.Range("B1:B" & lstrow)

for this:

For Each cell In ws.Range("B2:B" & lstrow)
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patrickabCommented:
Maybe as below...


Perhaps like this (to adapt jpp's code a little)

Dim wb As Workbook, ws As Worksheet
Dim cell As Range
Dim rng as Range
 
Set wb = ActiveWorkbook
Set ws = ActiveSheet
Set rng = ws.Range(ws.cells(2,"B"),ws.cells(ws.rows.count,"B").end(xlup))
 
For Each cell In rng
    cell=Round(cell,2)
Next cell

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patrickabCommented:
techpr0 - Thanks for the points - Patrick
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