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XSL Summation upon a node substring contidional

Posted on 2011-02-23
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Last Modified: 2013-11-18
Greetings,

The basic scenario is simple: sum a series of values.
<xsl:value-of select="sum(nodeA/nodeB/value)"/>

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The catch:
I want to sum all values except where the value of nodeB has a substring at the end the contains 2 specific characters. They are utilized as identifiers.

I know that this substring comparison works correctly (where Var2 has a string length of 2):
<xsl:when test="substring($Var1, (string-length($Var1) - string-length($Var2))+1) = 'XY'">

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So, I was thinking that I could apply that same logic within the summation methodology

<xsl:variable name="Var3" select="sum(nodeA/nodeB[substring(/ValueOfNodeB, (string-length(/ValueOfNodeB) - string-length('XY'))+1) != 'XY']/nodeC/nodeD)"/>

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I think that I am very close, and in fact the above line compiles and performs the summation, but doesn't perform the exclusion.

I would appreciate any thoughts or guidance.

Thanks in advance.
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Question by:nmluthy
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Expert Comment

by:Geert Bormans
ID: 34964658
the "/" makes the XPath return all values friom the root
I think you need

<xsl:variable name="Var3" select="sum(nodeA/nodeB[substring(., (string-length(.) - string-length('XY'))+1) != 'XY']/nodeC/nodeD)"/>

But basically this is the right approach and should work
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Geert Bormans earned 500 total points
ID: 34964672
safer is

<xsl:variable name="Var3" select="sum(nodeA/nodeB[not(substring(., (string-length(.) - string-length('XY'))+1) = 'XY')]/nodeC/nodeD)"/>

"=" in predicates is set compare, that could be tricky
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Author Comment

by:nmluthy
ID: 34964989
Thanks for you insight.

This will probably not look well upon me, but do you mean the "." as a literal or just shorthand notation for the values I had in there. I have seen "." used in much of the reference material I have found, but do not fully understand its purposed.

(If this is a totally new question I can move it to a new thread)

Thanks.
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Expert Comment

by:Geert Bormans
ID: 34965213
this is not a new question, don't worry

"." means the current node()
if you do eg.
nodeB[. = 'foo']
you will get all the nodeB that have the string 'foo' as content
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Author Comment

by:nmluthy
ID: 34965348
Makes sense; I'm glad to definitely have learned something today.

I really appreciate your help! I'm glad to find out that I was quite close, but in the same context it is rather frustrating. But everything seems to work well now.

Cheers!
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Expert Comment

by:Geert Bormans
ID: 34965517
welcome
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