asked on

Needs help in syntax

Hi guys: Can any one please tell me how to raise the power of any number for eg. 2 raise to power 3 = 8

Thanks.

#include <iostream>
using namespace std;

int main()
{
int number = 0;
       int power1 = 0;
       cout << "Enter Number to raise==>";
       cin >> number;
       cout << "Enter Power==>";
       cin >> power1;
       cout << number^power1; // syntax error
system("pause");
return 0;
}

mustish1

ASKER

I fix the syntax but it still wrong answer

#include <iostream>
using namespace std;

int main()
{
int number = 0;
       int power1 = 0;
       int result = 0;
       cout << "Enter Number to raise==>";
       cin >> number;
       cout << "Enter Power==>";
       cin >> power1;
       result = number^power1;
       cout << result << endl;
system("pause");
return 0;
}

ASKER CERTIFIED SOLUTION

MrNed

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mustish1

ASKER

Why it gives syntax error
result = pow(number,power1);

-----------------------
#include <iostream>
#include <math.h>
using namespace std;

int main()
{
int number = 0;
       int power1 = 0;
       int result = 0;
       cout << "Enter Number to raise==>";
       cin >> number;
       cout << "Enter Power==>";
       cin >> power1;
       result = pow(number,power1);
       cout << result << endl;
system("pause");
return 0;
}

MrNed

No idea about a syntax error, but check your types. It returns a float/double and the first parameter might need to be casted to a double. Try this:

result = (int)pow((double)number,power1);

mustish1

ASKER

Thanks.

crysallus

It might not know which version of the function to call as your number variable is an int, which doesn't match any of the pow methods exactly. Try:

result = pow((double)number, power1);

which casts the variable number to a double before calling the function, which specifies that it should call that version of the pow function.