Solved

Needs help in syntax

Posted on 2011-02-23
6
351 Views
Last Modified: 2012-05-11
Hi guys: Can any one please tell me how to raise the power of any number for eg. 2 raise to power 3 = 8

Thanks.

#include <iostream>
using namespace std;

int main()
{
      int number = 0;
        int power1 = 0;
        cout << "Enter Number to raise==>";
        cin >> number;
        cout << "Enter Power==>";
        cin >> power1;
        cout << number^power1;  // syntax error
      system("pause");
      return 0;
}  
0
Comment
Question by:mustish1
  • 3
  • 2
6 Comments
 

Author Comment

by:mustish1
ID: 34966974
I fix the syntax but it still wrong answer

#include <iostream>
using namespace std;

int main()
{
      int number = 0;
        int power1 = 0;
        int result = 0;
        cout << "Enter Number to raise==>";
        cin >> number;
        cout << "Enter Power==>";
        cin >> power1;
        result = number^power1;
        cout << result << endl;
      system("pause");
      return 0;
}  
0
 
LVL 7

Accepted Solution

by:
MrNed earned 500 total points
ID: 34967000
0
 

Author Comment

by:mustish1
ID: 34967012
Why it gives syntax error
  result = pow(number,power1);

-----------------------
#include <iostream>
#include <math.h>
using namespace std;

int main()
{
      int number = 0;
        int power1 = 0;
        int result = 0;
        cout << "Enter Number to raise==>";
        cin >> number;
        cout << "Enter Power==>";
        cin >> power1;
        result = pow(number,power1);
        cout << result << endl;
      system("pause");
      return 0;
}  
0
Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

 
LVL 7

Expert Comment

by:MrNed
ID: 34967026
No idea about a syntax error, but check your types. It returns a float/double and the first parameter might need to be casted to a double. Try this:

result = (int)pow((double)number,power1);
0
 

Author Closing Comment

by:mustish1
ID: 34967036
Thanks.
0
 
LVL 8

Expert Comment

by:crysallus
ID: 34967039
It might not know which version of the function to call as your number variable is an int, which doesn't match any of the pow methods exactly. Try:

result = pow((double)number, power1);

which casts the variable number to a double before calling the function, which specifies that it should call that version of the pow function.
0

Featured Post

Free Tool: Port Scanner

Check which ports are open to the outside world. Helps make sure that your firewall rules are working as intended.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

The purpose of this article is to demonstrate how we can use conditional statements using Python.
This is an explanation of a simple data model to help parse a JSON feed
The goal of the video will be to teach the user the difference and consequence of passing data by value vs passing data by reference in C++. An example of passing data by value as well as an example of passing data by reference will be be given. Bot…
In this fifth video of the Xpdf series, we discuss and demonstrate the PDFdetach utility, which is able to list and, more importantly, extract attachments that are embedded in PDF files. It does this via a command line interface, making it suitable …

809 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question