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Shell Script

Posted on 2011-02-24
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Last Modified: 2012-08-14
Need a script for below .

896019990060000001 502195560000001 43197381 1234 1234 48694743 DFC40A06BB8A2B63A63A98E5B3ACD4BA 03300349
896019990060000002 502195560000002 07536851 1234 1234 54280393 C781699B7735B9D8B30D1B4BAE970344 56623200
896019990060000003 502195560000003 29000945 1234 1234 29681079 356EEB858937C38B4A4C9245E89D68D7 78562572



I want to print col1 , col2 col 6 sepratly to a file they are seprarted by single space.
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Question by:ratna1234
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9 Comments
 
LVL 8

Expert Comment

by:ssnkumar
ID: 34968140
cut command on Unix/Linux will do this.
Use -f and -d options to indicate the field and the delimiter (in your case this is space or ' ').
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Expert Comment

by:omarfarid
ID: 34969172
use

cut -f 1,2,6 < datafile > myfile
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LVL 8

Expert Comment

by:ssnkumar
ID: 34969491
@omarfarid: I could have also given the full command with all the options. The reason I didn't give the full command is, it will be like doing the homework!
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Expert Comment

by:point_pleasant
ID: 34970635
there is of course the good ole awk command

awk '{ print $1" " $2" " $6 }'  filename
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LVL 48

Expert Comment

by:Tintin
ID: 34975693
awk '{print $1,$2,$6'} file >newfile

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Expert Comment

by:Tintin
ID: 34975700
Typo in my last comment.

Should be:

awk '{print $1,$2,$6'} file >newfile

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Expert Comment

by:point_pleasant
ID: 34976214
WOW

> newfile

really?
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Expert Comment

by:Tintin
ID: 34977793
point pleasant,

not sure what you mean.
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Accepted Solution

by:
Tintin earned 500 total points
ID: 34977795
bah, still had a typo

      

awk '{print $1,$2,$6}' file >newfile

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