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Query UPDATE report

Posted on 2011-02-24
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Last Modified: 2012-05-11
I have a script that updates a database.  It updates about 100 field from information that is being parsed from a feed.  What type of query code would I need to write so that the UPDATE that ran would report to me the fields that were updated?
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Question by:rgranlund
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7 Comments
 
LVL 17

Expert Comment

by:nanharbison
ID: 34973233
can you give us the update query as it is written now?
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LVL 7

Author Comment

by:rgranlund
ID: 34973283
@nanharbison

$q = "UPDATE exp_weblog_data SET field_id_29='$field_id_29', field_id_30='$field_id_30', field_id_31='$field_id_31'  WHERE field_id_215='$field_id_215'";


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LVL 17

Accepted Solution

by:
nanharbison earned 500 total points
ID: 34973527
How about this?
$q = "UPDATE exp_weblog_data SET field_id_29='$field_id_29', field_id_30='$field_id_30', field_id_31='$field_id_31'  WHERE field_id_215='$field_id_215'"; 

if ($return = mysql_query($q, $yourconnection))
{
	send yourself an email;
)

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LVL 17

Expert Comment

by:nanharbison
ID: 34973539
Do you know how to send email in PHP? You could include the values you updated if you want to see them.
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LVL 7

Author Comment

by:rgranlund
ID: 34973606
I want to print the return on screen.  Can I echo $q?
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LVL 17

Expert Comment

by:nanharbison
ID: 34973639
Absolutely, you can echo the query!
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LVL 17

Expert Comment

by:nanharbison
ID: 34973649
You can do this
$q = "UPDATE exp_weblog_data SET field_id_29='$field_id_29', field_id_30='$field_id_30', field_id_31='$field_id_31'  WHERE field_id_215='$field_id_215'"; 

if ($return = mysql_query($q, $yourconnection))
{
	echo $q;
)

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