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Object Sorting

Posted on 2011-02-24
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Last Modified: 2012-06-22
import java.util.*;
public class Employee{
Date DOB = new Date(0L);
}

I have different Employee objects with different DOB's. I want to sort Employee object based on DOB field. How to do that? Please suggest with the detailed explanation!!
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Question by:sumanthpuvvula
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by:sumanthpuvvula
ID: 34977229
all Employee Objects are in a ArrayList ..... so I need to sort that arrayList based on the date object in Employee
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Expert Comment

by:for_yan
ID: 34977263
You just override compareTo method for your class Employee and then Collections.sort(ArrayList) will work fo you.
I'll preprae some code for you
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for_yan earned 250 total points
ID: 34977269
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by:objects
ID: 34977290
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by:for_yan
ID: 34977298

Well, the exmample above in fact uses your case with Employee and dates.
Basically you need to add to your class definition "implements Comparable"
and then add method int compare (Employee e1, Employee e2) as shown below.

That would be enough then after Collections.sort(al);
where al is ArrayList of your employyee, thelist al will become sorted

public class Employee implements Comparable {

    public int compare(Employee e1, Employee e2) {
        int dateCmp = e2.hireDate().compareTo(e1.hireDate());
        if (dateCmp != 0)
            return dateCmp;
        return (e1.number() < e2.number() ? -1 :
                (e1.number() == e2.number() ? 0 : 1));
    }

}



}
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Assisted Solution

by:CEHJ
CEHJ earned 250 total points
ID: 34978629
>>I want to sort Employee object based on DOB field. How to do that?

If you're using Comparable, you just need
public class Employee implements Comparable<Employee> {
...
	public int compare(Employee e1, Employee e2) {
		return e1.DOB.compareTo(e2.DOB);
	}

}

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by:Dhaest
ID: 35321641
This question has been classified as abandoned and is being closed as part of the Cleanup Program. See my comment at the end of the question for more details.
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