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causing an error in my syntax for my validating my form for my database

Posted on 2011-02-26
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Last Modified: 2013-11-13
I am still having  problems with sending my info to my database its not validating and  this is the error that is telling me
Parse error: syntax error, unexpected T_BOOLEAN_AND
 validate1.html
 validate1a.php
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Question by:imagekrazy
  • 5
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7 Comments
 
LVL 14

Accepted Solution

by:
Scott Madeira earned 500 total points
ID: 34988715
You have a syntax error onlines 18 and 19 (your two if statements...   Too many parenthesis and not teh same number of opens and closes.  Try these:

if ( !empty($frstname) && !empty($lstname) )     {
      
            if (!empty($email) || !empty($about_yourself)) {
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Author Comment

by:imagekrazy
ID: 34989408
Hi, I did that , and it spit out an error--

Parse error: syntax error, unexpected '{' in


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>front page form</title>
</head>

<body>
<h2>  Please fill out the form or it wont be sent!</h2>

<?php
   
    $frstname= $_POST['frstname'];
    $lstname= $_POST['lstname'];
    $email= $_POST['email'];
    $about_yourself= $_POST['about_yourself'];
      
if(!empty($frstname)&&(!empty($lstname))     {
      
            if(!empty($email) || (!empty($about_yourself)) {
                  
            

$dbc = mysqli_connect('myvebsite.db.2150637.hostedresource.com','myvebsite','Jeep123','myvebsite')
or die('Error connecting to MySQL server.');

$query= "INSERT INTO emaills_hhl (frstname,lstname,email,about_yourself)".
         "VALUES ('$frstname','$lstname','$email','$about_yourself')";
             
$data = mysqli_query($dbc,$query)
or die('MySQL error:' . mysqli_error($dbc) . "<hr>\nQuery: $query");

//$result = mysqli_query($dbc,$query)
       // or die('Error query database.');
            //or die('Error:' .mysqli_error($dbc));
            
 while ($row = mysqli_fetch_array($result)){
      $to =$row['email'];
      $frstname = $row['frstname'];
      $lstname = $row['lstname'];
      $about_yourself = $row['about_yourself'];
      $msg = "Dear $frstname $lstname $about_yourself ,\n$text";
      mail($to,$subject,$msg,'From:' . $from);
      echo 'Email senbt to '.$to. '<br>';
  }
            

mysqli_close($dbc);
                  }
            }
      
 

//      echo 'Thanks for submitting the form.<br/>';
//      echo 'Your first name ' . $frstname.'<br/>';
//      echo 'Your last name ' . $lstname.'<br/>';
//      echo 'Your email ' . $email.'<br/>';
//      echo 'Your message '.$about_yourself;
      
      
      
      ?>
      
      
</body>
</html>
0
 

Author Comment

by:imagekrazy
ID: 34989427
oops i missed two {{ then i did it again and it is saying this;

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in
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LVL 14

Expert Comment

by:Scott Madeira
ID: 34990105
You changed variable names.  you have:

$data = mysqli_query($dbc,$query)
or die('MySQL error:' . mysqli_error($dbc) . "<hr>\nQuery: $query");


which executes the query.  Then you have these commented lines

//$result = mysqli_query($dbc,$query)
       // or die('Error query database.');
            //or die('Error:' .mysqli_error($dbc));
           
Here you are trying to use $result as your result set but you used $data for the query result above.

 while ($row = mysqli_fetch_array( $result  )){
      $to =$row['email'];
      $frstname = $row['frstname'];
      $lstname = $row['lstname'];
      $about_yourself = $row['about_yourself'];
      $msg = "Dear $frstname $lstname $about_yourself ,\n$text";
      mail($to,$subject,$msg,'From:' . $from);
      echo 'Email senbt to '.$to. '<br>';
0
 

Author Comment

by:imagekrazy
ID: 34991515
Its still giving me  the error

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean

my code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>front page form</title>
</head>

<body>
<h2>  Please fill out the form or it wont be sent!</h2>

<?php
   
    $frstname= $_POST['frstname'];
    $lstname= $_POST['lstname'];
    $email= $_POST['email'];
    $about_yourself= $_POST['about_yourself'];
      
if(!empty($frstname)&&!empty($lstname))     {
      
            if(!empty($email) ||!empty($about_yourself)) {
                  
            

$dbc = mysqli_connect('myvebsite.db.2150637.hostedresource.com','myvebsite','Jeep123','myvebsite')
or die('Error connecting to MySQL server.');

$query = "INSERT INTO emaills_hhl (frstname,lstname,email,about_yourself)".
         "VALUES ('$frstname','$lstname','$email','$about_yourself')";
             
$query = mysqli_query($dbc,$query)
or die("MySQL error:" . mysqli_error($dbc) . "<hr>\nquery: $query");


            
 while ($row = mysqli_fetch_array($query)){
      $to =$row['email'];
      $frstname = $row['frstname'];
      $lstname = $row['lstname'];
      $about_yourself = $row['about_yourself'];
      $msg = "Dear $frstname $lstname $about_yourself ,\n$text";
      mail($to,$subject,$msg,'From:' . $from);
      echo 'Email senbt to '.$to. '<br>';
  }
            

mysqli_close($dbc);
                  }
            }
      
 


      
      
      
      ?>
      
      
</body>
</html>
0
 

Author Comment

by:imagekrazy
ID: 34991847
i hit the wrong button
0
 

Author Closing Comment

by:imagekrazy
ID: 34991851
thanks, I am going to re post it after i fix a few things
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