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How to use filter_has_var in php?

Posted on 2011-02-27
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Medium Priority
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Last Modified: 2012-05-11
I tried writing an if statement like this:

if (filter_has_var(INPUT_POST, 'hw1')) {
      $hw1 = filter_input(INPUT_POST, 'hw1');
}
else {
      $hw1 = 100;      
}

But Its not working. I get this error message:

Notice: Use of undefined constant hw1 - assumed 'hw1' in /home/tleithof/htdocs/gradebook.php on line 13

Warning: filter_has_var() expects exactly 2 parameters, 1 given in /home/tleithof/htdocs/gradebook.php on line 13

Can someone please inform how to use this function corrently?? Thanks
0
Comment
Question by:FairyBusiness
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3 Comments
 
LVL 17

Accepted Solution

by:
Dushan De Silva earned 2000 total points
ID: 34993995
http://www.w3schools.com/php/func_filter_has_var.asp
http://www.w3schools.com/PHP/php_filter.asp
http://php.net/manual/en/function.filter-has-var.php
---------------------------------------------------------------------
if (filter_has_var(INPUT_POST, "hw1"))
{
      $hw1 = filter_input(INPUT_POST, "hw1");
}
else {
      $hw1 = 100;      
}
---------------------------------------------------------------------
<?php
if(!filter_has_var(INPUT_POST, "url"))
  {
  echo("Input type does not exist");
  }
else
  {
  $url = filter_input(INPUT_POST, "url", FILTER_SANITIZE_URL);
  }
?> 

----------------------------------------------------------------------

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0
 

Author Comment

by:FairyBusiness
ID: 34994008
I dont see how you changed my code.  But does the function not work unless you use ! before it??
0
 

Author Closing Comment

by:FairyBusiness
ID: 34994085
Ok, yes you must use !
Thanks
0

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