Help with SQL Update query

Hi Experts!

I have 2 tables with customers
Tab_Customers have the following record layout.

Customerno,
Firstname,
lastname,
adresse,
Zip,
City,
Phone,

Tab_Phone has the following recordlayout

Tab_Phone
Customerno
Firstname,
lastname,
adresse,
Zip,
City,
Phone

In Tab_Customers there is no phone numbers present
In Tab_Phone there are no customernumbers present, but it has phone numbers present.

I would like to add the customer number to the Tab_Phone table where ever there is a big similarity on the name.

I have tried the following:

update Tab_Phone
set Customerno = (
select c.Customerno from Tab_Customers c where exists(select * from Tab_Phone p where
similar (p.Firstname,c.firstname)<99 and
similar (p.Lastname,c.lastname)<99 and
similar (p.Adresse,c.adresse)<99 and
similar (p.zip,c.zip)<99 and
similar (p.City,c.City)<99)
)

Is someone able to help me?

regards
gfk76
gfk76Asked:
Who is Participating?
 
reb73Connect With a Mentor Commented:
If you check for a result value below 99 for the similar function, you will indeed get the same customer code for all rows.. It will end up matching the first record (not necessarily the same but likely) for all record sin Tab_Phone.

See the function reference below -

http://www.mssqltips.com/tip.asp?tip=1782

I believe you should be checking for >99 in the where clause -

(Suggestion: Start with >99 and reduce by one until 90, review the code below which resets the customerno and then loops through until it can populate as many customerno values as possible, you may still have to disable the matching on zip, city and address eventually to get a good population)
update Tab_Phone set Customerno = null -- This will reset the customer no initially

Declare @matchlevel int
set @matchlevel = 99

while @matchlevel >= 90
begin
	update p
	set Customerno = c.CustomerNo
	from  Tab_Phone p
	inner join Tab_Customers c on
	    similar (p.Firstname,c.firstname)> @matchlevel and
	    similar (p.Lastname,c.lastname)> @matchlevel and
	    similar (p.Adresse,c.adresse)> @matchlevel and
	    similar (p.zip,c.zip)> @matchlevel and
	    similar (p.City,c.City)> @matchlevel)
	where p.Customerno is null

	set @matchlevel = @matchlevel - 1
end

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0
 
reb73Commented:
Do you have a UDF called similar or are you trying to hint that you'd like to use a function that will act on similarity?

You could try the query below but it tries to match based on how the names sound when pronounced and may not be very accurate -

 
update p
set Customerno = c.customerno
from  Tab_Phone p
inner join Tab_Customers c on
	difference(p.Firstname, c.firstname)	> 3
and	difference(p.Lastname,c.lastname)	> 3
and	difference(p.Adresse,c.adresse)		> 3
and	difference(p.zip,c.zip)			> 3
and	difference(p.City,c.City)		> 3

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0
 
gfk76Author Commented:
Hi reb73!

Thank you for trying to help.
I should probably told you that it is a Sybase database.
Similar is a built in function in iAnywhere, that checks for similareties.

I tryed your query with similar instead of difference

update p
set Customerno = c.CustomerNo
from  Tab_Phone p
inner join Tab_Customers c on
    similar (p.Firstname,c.firstname)<99 and
    similar (p.Lastname,c.lastname)<99 and
    similar (p.Adresse,c.adresse)<99 and
    similar (p.zip,c.zip)<99 and
    similar (p.City,c.City)<99)

I get following error message
"Table p not found"

Any idea?
0
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reb73Commented:
Try changing the first line from

update p

to

update Tab_Phone
0
 
gfk76Author Commented:
This updates with the same customer number on all rows
0
 
SharathData EngineerCommented:
Can you check this?
update Tab_Phone
   set Tab_Phone.Customerno = Tab_Customers.CustomerNo
  from Tab_Phone,Tab_Customers 
 where similar (Tab_Phone.Firstname,Tab_Customers.firstname)<99 and
       similar (Tab_Phone.Lastname,Tab_Customers.lastname)<99 and
       similar (Tab_Phone.Adresse,Tab_Customers.adresse)<99 and
       similar (Tab_Phone.zip,Tab_Customers.zip)<99 and
       similar (Tab_Phone.City,Tab_Customers.City)<99)

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reb73Commented:
Correction: Please change line 8 as follows -

update Tab_Phone
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gfk76Author Commented:
Arggghhhh.....

Thank you so much......
I have been working on this query for 1 and a half day now.....
I cant belive I missed it.

You have saved my day, and tonight my sleep :-)
0
 
reb73Commented:
Glad to help! Cheers..
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