Need help with WHERE clause in LINQ trying to use a wildcard

I am asking the user to key in a code to lookup.  I want them to be able to key in just part of the code and my result come back with the closest match to their partial entry in the field.  Example.

Actual Code: 234.32

They key in:
23   -  it would return in the list
234 - it would return in the list
234. it would return in the list.

Can someone show me where I am goin wrong?


var ICD9Result = from ICD9data in dc1234.ICD9s
                                 where ICD9data.ICD9_cd.ToString().StartsWith("@"+tbDiagCodeLookup.ToString())
                                 select new { ICD9data.ICD9_cd, ICD9data.Name };

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kwh3856Asked:
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Fernando SotoRetiredCommented:
Hi Kenny;

The error is that you have prepend a @ to the search string. So what you are sending to the server is @23, @234 and @234.So remove the @ sign. So try it like this:

var ICD9Result = from ICD9data in dc1234.ICD9s
                     where ICD9data.ICD9_cd.ToString().StartsWith(tbDiagCodeLookup.ToString())
                     select new { ICD9data.ICD9_cd, ICD9data.Name };

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There is a better way which gives more flexibility and that is to use the T-SQL Like command in the query as follows:

using System.Data.Linq.SqlClient;                 
                 
string pattern = "23%";

var ICD9Result = from ICD9data in dc1234.ICD9s
                 where SqlMethods.Like(ICD9data.ICD9_cd.ToString(), pattern)
                 select new { ICD9data.ICD9_cd, ICD9data.Name };                 

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The pattern can be any T-SQL Like meta-characters.

Fernando
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HugoHiaslCommented:
What for is the @ character?  This one is normally used if you use predefined varaibles what you do not do here.
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kwh3856Author Commented:
I thought that was the wildcard symbol.  If not...what is a wildcard symbol in LINQ?
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Fernando SotoRetiredCommented:
Hi Kenny;

To your question, "I thought that was the wildcard symbol.  If not...what is a wildcard symbol in LINQ?", When you use the Startswith the function takes your string and adds a % to the end of the string. Using the SqlMethods.Like you place the meta-characters where you like  using the T-SQL Like pattern characters found here.

Fernando
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kwh3856Author Commented:
Fernando
Thank you very much. I appreciate it when you answer my questions because I am always learning something new. Thanks
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Fernando SotoRetiredCommented:
Not a problem Kenny, always glad to help.  ;=)
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